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Phoenix [80]
4 years ago
6

Part a a solution is made by mixing 9.00 mmol (millimoles) of ha and 3.00 mmol of the strong base. what is the resulting ph? exp

ress the ph numerically to two decimal places.
Chemistry
1 answer:
Debora [2.8K]4 years ago
7 0

Assuming that the reaction is unimolecular on both reactant and product sides such that:

 

HA  +  OH-   -->  A-  +  H2O

 

Therefore the amount of A- left is:

mmol HA = 9.00 - 3.00 = 6.00 <span>
mmol A- = 3.00 

pKa = - log Ka = 5.25 

</span>

<span>Calculating for pH:
pH = 5.25 + log 3.00/6.00</span>

<span>pH = 4.95 </span>
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