The density of any substance does not change at a certain temperature and pressure. Even though mass and volume are intensive properties (depends on the amount of substance), density is not. It is merely a fixed ratio of mass to volume. Therefore, the solution is
Density = Mass/Volume
For your information, quantitatively, cm³ is equivalent to mL.
Density = 100 g/4.67 cm³ = 21.41 g/cm³
Answer: AgNO3 is the limiting reactant.
Explanation:
1) Balanced chemical equation:
<span>Given: 2AgNO3 + NiCl2 → 2AgCl + Ni(NO3)2
2) Mole ratios:
2 mol AgNO3 : 1 mol NiCl2 : 2 mol AgCl : 1 mol Ni(NO3)2
3) Convert 0.847 g of AgNO3 to moles
n = mass in grams / molar mass
molar mass = sum of the masses of all the atoms in the molecular formula
molar mass of AgNO3 = 107.9 g/mol + 14.0 g/mol + 3*16.0 g/mol = 169.9 g/mol
n = 0.847 g / 169.9 g/mol = 0.00499 mol AgNO3
4) Convert 0.650 g of NiCl2 to moles
n = mass in grams / molar mass
molar mass NiCl2 = 58.7 g/mol + 2*35.5 g/mol = 129.7 g/mol
n = 0.650 g / 129.7 g/mol = 0.00501 mol NiCl2
5) Compare the theoretical mole ratio with the actual ratio:
Theoretical mole ratio: 2 mol AgNO3 / 1 mol NiCl2
Actual ratio: 0.00499 mol AgNO3 / 0.00501 mol Ni Cl2 ≈ 1:1
Therefore, the amount of AgNO3 is half the required amount need to react with all the NiCl2, which means that the AgNO3 will react completely and there will be an excess of NiCl2. The reactant that is consumed completely while the other is left, is the limiting reactan. This is, AgNO3 is the limiting reactant.</span>
The units are nm (nano-meter), km (kilo-meter), pm (pico-meter), dm (decimeter), mm (millimeter), m (meter), cm (centimeter), hm (hectometer) and gm (gigameter). Now we can express each of these units in terms of m.
1 nm = 
, 1 Km = 
1 pm = 
, 1 dm = 0.1 m, 1 mm = 0.001 m, 1 cm = 0.01 m, 1 hm = 100 m, 1 gm = 
. Thus the decreasing unit will be
gm>km>hm>m>dm>cm>mm>nm>pm
Answer:
moles B = 2.32 moles
Explanation:
In this case, we can assume that both gases are ideals, so we can use the expression for an ideal gas which is:
PV = nRT
From here, we can calculate the total moles (n) that are in the container, and then, by difference, we can calculate how much we have of gas B.
For this case, we will use R = 0.082 L atm / mol K. Solving for n:
n = PV/RT
n = 5 * 20 / 0.082 * 303
n = 4.02 moles
If we have 4.02 moles between the two gases, and we have 1.70 from gas A, then from gas B we simply have:
Total moles = moles A + moles B
moles B = Total moles - moles A
moles B = 4.02 - 1.70
moles B = 2.32 moles
We have 2.32 moles of gas B
Answer:
An aquifer is a layer of porous substrate that contains and transmits groundwater. ... The upper level of this saturated layer of an unconfined aquifer is called the water table or phreatic surface. Below the water table, where in general all pore spaces are saturated with water, is the phreatic zone.
