A. The abundance of the 2nd isotope is 48.119%
B. The mass of the 2nd isotope is 108.905 amu
Let the 1st isotope be A
Let the 2nd isotope be B
A. Determination of the abundance of the 2nd isotope
Abundance of isotope A = 51.881%.
<h3>Abundance of isotope B =? </h3>Abundance of B = 100 – A
Abundance of B = 100 – 51.881
<h3>Abundance of B = 48.119%</h3>B. Determination of the mass of the 2nd isotope
Atomic mass of silver = 107.868 amu.
Mass of 1st isotope (A) = 106.906 amu
Abundance of isotope A (A%) = 51.881%.
Abundance of isotope B (B%) = 48.119%
<h3>Mass of 2nd isotope (B) =? </h3>Therefore, the mass of the 2nd isotope is 108.905 amu
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