Answer:
Explanation:
change in momentum = m ( v - u ) ; m is mass , V is final velocity and u is initial velocity .
= 250 ( 28 - 6 )
= 5500. N.s
for calculating magnitude of force we shall apply the concept of impulse
Impulse = F X t = m( v-u ) ; F is force applied for time t .
F x 60 = 5500
F = 91.67 N .
force exerted = 91.67 N .
Answer:
7557120 kg/hour
Explanation:
Given data;
Volume of air in one second = 1640 L
Density of air = 1.28 kg/L
Mass of air in 1 hour =?
Since mass = density × volume
==> Mass of air in one second = 1.28 ×1640 = 2099.2 kg
==> Mass of air in one minute = 2099.2×60=125952 kg
==> Mass of air in one hour = 125952× 60 = 7557120 kg
So rate of flow of air is 7557120 kg/hour
Answer : The volume of water in the pool is, 2473 ft³
Explanation :
First we have to calculate the average depth.
Given:
Diameter = 30 ft
Depth range : 1 to 6 ft linearly
average depth =
Now we have to calculate the volume of water in the pool.
Volume = area × average depth
V = π × (radius)² × 3.5
V = π × (30/2)² × 3.5
V = π × (15)² × 3.5
V = π × 225 × 3.5
V = 3.14 × 225 × 3.5
V = 2472.75 ft³ ≈ 2473 ft³
Therefore, the volume of water in the pool is, 2473 ft³
When the resultant force is not equal to zero termed an unbalanced force. By procedures 4 and 5 students observe an unbalanced upward force on Box 1. Hence option 1 is right for the problem.
<h3>What is an unbalanced force?</h3>
The forces operating on a body are known as unbalanced forces when the resulting force exerted on it is not equal to zero.
Unbalanced forces acting on the body, causing it to modify its state of motion. To further grasp the nature of imbalanced forces.
<h3 />
The following reasons by which we can understand the unbalanced force caused by the box.
Due to these two reasons, books will move up.
By adding another mass to box 2. The box becomes lighter. As the box becomes lighter the gravity force acting on the box will be less due to which the box easily can move up.
By removing the two masses from box 1. Due to which other become heavier other becomes heavier pulling it down causing box 1 one to go up.
Hence by procedures 4 and 5 students observe an unbalanced upward force on Box 1. Hence option 1 is right for the problem.
To learn more about the unbalanced force refer to the link;
brainly.com/question/227461
