Answer:
C 2000v its obviously ans because if o is 1000 2 vo is 2000v
Self productive and it depends on how whom is behaving.
The ball's gravitational potential energy is converted into kinetic energy as it falls toward the ground.
<h3>How can the height of a dropped ball be determined?</h3>
Y = 1/2 g t 2, where y is the height above the ground, g = 9.8 m/s2, and t = 1.3 s, is the formula for problems like these. Any freely falling body with an initial velocity of zero meters per second can use this formula. figuring out how much y is.
A ball drops from the top of a building and picks up speed as it descends. Its speed is increasing by 10 m/s every second. What we refer to as motion with constant acceleration is, for example, a ball falling due to gravity.
The ball's parabolic motion causes it to move at a speed of 26.3 m/s right before it strikes the ground, which is faster than its straight downhill motion, which has a speed of 17.1 m/s. Take note of the rising positive y direction in the above graphic.
To Learn more About potential energy, Refer:
brainly.com/question/14427111
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Answer:
![-0.25 rad/s^2](https://tex.z-dn.net/?f=-0.25%20rad%2Fs%5E2)
Explanation:
The equivalent of Newton's second law for rotational motions is:
![\tau = I \alpha](https://tex.z-dn.net/?f=%5Ctau%20%3D%20I%20%5Calpha)
where
is the net torque applied to the object
I is the moment of inertia
is the angular acceleration
In this problem we have:
(net torque, with a negative sign since it is a friction torque, so it acts in the opposite direction as the motion)
is the moment of inertia
Solving for
, we find the angular acceleration:
![\alpha = \frac{\tau}{I}=\frac{-12.5 Nm}{50.0 kg m^2}=-0.25 rad/s^2](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B%5Ctau%7D%7BI%7D%3D%5Cfrac%7B-12.5%20Nm%7D%7B50.0%20kg%20m%5E2%7D%3D-0.25%20rad%2Fs%5E2)