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mina [271]
3 years ago
8

Answer pls pls plss this is my mock

Chemistry
1 answer:
Serggg [28]3 years ago
4 0

Answer:

if this is a mock then just guess

Explanation:

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3 years ago
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6 0
3 years ago
Calculate the change in ph when 3.00 ml of 0.100 m hcl(aq) is added to 100.0 ml of a buffer solution that is 0.100 m in nh3(aq)
nikklg [1K]

The change in pH is calculated by:

pOH = Protein kinase B + log [NH4+]/ [NH3] 

Protein kinase B of ammonia = 4.74 

initial potential of oxygen hydroxide= 4.74 + log 0.100/0.100 = 4.74 
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moles NH4+ = moles NH3 = 0.100 L x 0.100 M = 0.0100 
moles H+ added = 3.00 x 10^-3 L x 0.100 M=0.000300 

NH3 + H+ = NH4+ 
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the change is  = 9.26 - 9.23 =0.03 

7 0
3 years ago
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