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Kobotan [32]
3 years ago
5

Equation of a plane find the equation of the plane that is parallel to the vectors 〈 1 , − 3 , 1 〉 and 〈 4 , 2 , 0 〉 , passing t

hrough the point ( 3 , 0 , − 2 ) .
Mathematics
1 answer:
Lelechka [254]3 years ago
6 0
(1)Identify the surface whose equation is r = 2cosθ by converting first to rectangular coordinates...(2)Identify the surface whose equation is r = 3sinθ by converting first to rectangular coordinates...(3)Find an equation of the plane that passes through the point (6, 0, −2) and contains the line x−4/−2 = y−3/5 = z−7/4...(4)Find an equation of the plane that passes through the point (−1,2,3) and contains the line x+1/2 = y+2/3 = z-3/-1...(5)Find a) the scalar projection of a onto b b) the vector projection of a onto b given = 〈2, −1,3〉 and = 〈1,2,2〉...(6)Find a) the scalar projection of a onto b b) the vector projection of a onto b given = 〈2,1,4〉 and = 〈3,0,1〉...(7)Find symmetric equations for the line of intersection of the planes x + 2 y + 3z = 1 and x − y + z = 1...(8)Find symmetric equations for the line of intersection of the planes x + y + z = 1 and x + 2y + 2z = 1...(9)Write inequalities to describe the region consisting of all points between, but not on, the spheres of radius 3 and 5 centered at the origin....(10)Write inequalities to describe the solid upper hemisphere of the sphere of radius 2 centered at the origin....(11)Find the distance between the point (4,1, −2) and the line x = 1 +t , y = 3 2−t , z = 4 3−t...(12)Find the distance between the point (0,1,3) and the line x = 2t , y = 6 2−t , z = 3 + t...(13)Find a vector equation for the line through the point (0,14, −10) and parallel to the line x=−1+2t, y=6-3t, z=3+9t<span>...</span>
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I think the answer is 151.
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3 years ago
A diver descends to a location of -50 1 over 4 meters relative to the surface of the water. He then descends another 10 1 over 2
Yanka [14]

Answer:

-60\frac{3}{4} meters.

Step-by-step explanation:

To find diver's final location relative to the surface of water we will subtract  10\frac{1}{2} from -50\frac{1}{4} because diver dives away another 10\frac{1}{2} from his previous location of -50\frac{1}{4}.

-50\frac{1}{4} -10\frac{1}{2}

Now we will convert our mixed fraction into improper fraction and then we will find a common denominator.

\frac{-201}{4} -\frac{21}{2} =\frac{-201-42}{4}

=\frac{-243}{4}

Now let us convert our answer in mixed fraction.

=\frac{-243}{4}=[tex]-60\frac{3}{4}[/tex]

Therefore, diver's final location relative to the surface of the water is -60\frac{3}{4} meters.

3 0
3 years ago
Read 2 more answers
4 – 15 ÷ (30 – 33) =
cupoosta [38]

Answer: 9

Step-by-step explanation:

    We will use the Order of Operations to solve.

 Given:

4 – 15 ÷ (30 – 33)

 Subtract 33 from 30:

4 – 15 ÷ (– 3)

 Divide -15 by -3:

4 + 5

 Add 4 to 5:

9

7 0
2 years ago
Read 2 more answers
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