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Andreyy89
3 years ago
15

Asap, I need help

Chemistry
2 answers:
kati45 [8]3 years ago
4 0
A. Definitely one that can be produced as fast as it’s used
madreJ [45]3 years ago
3 0
A. One that can be produced as fast as it’s used
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Which statement best describes the compressibility of a gas?
atroni [7]

Hey there!


The answer to this question would most likely be the 3rd choice, (option C)


Increasing the pressure on a gas decreases the volume


Good luck on your assignment and enjoy your day!


~LoveYourselfFirst:)

7 0
3 years ago
In 1939, at the age of 20, a man stood 270 cm tall (over 8 1/2 feet) and wore size 37 shoes! The hormonal disorder from which he
rodikova [14]

Answer:

Somatotropin(Growth Hormone)

Explanation:

-Uncontrolled growth in a person is usually caused by the excessive secretion of growth hormone.

-This hormone is also known as Somatotropin.

-This hormone is produced  in the pituitary  gland.

3 0
3 years ago
Difference between pure and applied research
nata0808 [166]

Answer:

pure is water made by us

Explanation:

lap water are pured also but somtimes they are dirty

6 0
2 years ago
Read 2 more answers
Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibriumdescribed by the equation N2O4(g)↔
Vilka [71]

Answer : The correct option is, (C) 1.1

Solution :  Given,

Initial moles of N_2O_4 = 1.0 mole

Initial volume of solution = 1.0 L

First we have to calculate the concentration N_2O_4.

\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}

\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M

The given equilibrium reaction is,

                           N_2O_4(g)\rightleftharpoons 2NO_2(g)

Initially                      c                 0

At equilibrium   (c-c\alpha)           2c\alpha

The expression of K_c will be,

K_c=\frac{[NO_2]^2}{[N_2O_4]}

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

where,

\alpha = degree of dissociation = 40 % = 0.4

Now put all the given values in the above expression, we get:

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

K_c=\frac{(2\times 1\times 0.4)^2}{(1-1\times 0.4)}

K_c=1.066\aprrox 1.1

Therefore, the value of equilibrium constant for this reaction is, 1.1

4 0
3 years ago
2. What does the text list and describe?
Mariana [72]

Answer:

C. ways radiation is transferred into and through Earth's atmosphere

Explanation:

6 0
3 years ago
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