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Andreyy89
3 years ago
15

Asap, I need help

Chemistry
2 answers:
kati45 [8]3 years ago
4 0
A. Definitely one that can be produced as fast as it’s used
madreJ [45]3 years ago
3 0
A. One that can be produced as fast as it’s used
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If you start with 10ml of 0.75 m cu(no3)2 how much cu (s) in grams should be recovered in step #7
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<span>0.48 grams. Not a well worded question since it's assuming I know the reactions. But I'll assume that since there's just 1 atom of copper per molecule of Cu(NO3)2, that the reaction will result in 1 atom of copper per molecule of Cu(NO3)2 used. With that in mind, we will have 0.010 l * 0.75 mol/l = 0.0075 moles of copper produced. To convert the amount in moles, multiply by the atomic weight of copper, which is 63.546 g/mol. So 0.0075 mol * 63.546 g/mol = 0.476595 g. Round the results to 2 significant figures, giving 0.48 grams.</span>
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Molar mass of 4Fe(OH)2
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4 years ago
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<span>100,000 times more. The rule is that the product of the concentration of (H+) and (OH-) in molars is always 10^-14 (if it is more, they combine and produce simple water which brings the product back down to this number again. If it is less, water molecules will split to bring the product back up to equilibrium).
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