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diamong [38]
3 years ago
9

A chemistry student is given the task of analyzing the three unknown samples in the previous question. Compare the densities fro

m Samples A, B, and C above to the accepted densities of the substances below. Identify the unknown samples as being either aluminum, iron, nickel, or tin. Densities of Common Elements Element Name Density (g/cm3) Aluminum 2.701 g/cm3 Iron 7.86 g/cm3 Nickel 8.90 g/cm3 Tin 7.28 g/cm3 Sample A ______________________ Sample B ______________________ Sample C _______________________
Chemistry
1 answer:
OLEGan [10]3 years ago
6 0

Answer:

It’s B

Explanation:

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Wes melted some cheese over some tortilla chips to make nachos.
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Answer:

a

Explanation:

Because the mass would stay the same and the flavor did not change and neither did the color so the shape is the only thing that changed

4 0
3 years ago
Please help me I will give a brainleist​
Korvikt [17]
When the dew point temperature and air temperature are equal, the air is said to be saturated. Dew point temperature is NEVER GREATER than the air temperature. Therefore, if the air cools, moisture must be removed from the air and this is accomplished through condensation.
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Wich stament describes to organ systems working together to get rid of waste played by cells
IceJOKER [234]

Answer:

C. Kidneys filter wastes from the bloodstream and produce urine

Explanation:

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2 years ago
Read 2 more answers
Please someone answer and help :) ​
algol [13]
13. D
14. A
15. C
16. B
17. F
18. E
7 0
2 years ago
NH4NO3, whose heat of solution is 25.7 kJ/mol, is one substance that can be used in cold pack. If the goal is to decrease the te
makvit [3.9K]

Answer:

There are necessaries 35,2g of NH₄NO₃ per 100,0g of water to decrease the temperature of the solution from 25,0°C to 5,0°C

Explanation:

To decrease the temperature of the solution there are necessaries:

4,184J/g°C×(5,0°C-25,0°C)×(100,0g+X) = -Y

8368J + 83,68J/gX = Y <em>(1)</em>

Where x are grams of NH₄NO₃ you need to add and Y is the energy that you need to decrease the heat.

Also, the energy Y will be:

Y = 25700J/mol×\frac{1mol}{80,043g}X

Y = 321J/g X <em>(2)</em>

Replacing (2) in (1)

8368J + 83,68J/g X = 321J/g X

8363J = 237,32J/gX

<em>X = 35,2g</em>

<em />

Thus, there are necessaries 35,2g of NH₄NO₃ per 100,0g of water to decrease the temperature of the solution from 25,0°C to 5,0°C

I hope it helps!

6 0
3 years ago
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