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diamong [38]
3 years ago
9

A chemistry student is given the task of analyzing the three unknown samples in the previous question. Compare the densities fro

m Samples A, B, and C above to the accepted densities of the substances below. Identify the unknown samples as being either aluminum, iron, nickel, or tin. Densities of Common Elements Element Name Density (g/cm3) Aluminum 2.701 g/cm3 Iron 7.86 g/cm3 Nickel 8.90 g/cm3 Tin 7.28 g/cm3 Sample A ______________________ Sample B ______________________ Sample C _______________________
Chemistry
1 answer:
OLEGan [10]3 years ago
6 0

Answer:

It’s B

Explanation:

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Figure 2 shows what happens to the electrons in the outer shells when a sodium atom reacts with a fluorine atom.
QveST [7]

Sodium reacts with fluorine to make a covalent bond between them.  A covalent bond is formed when there is a mutual sharing of electrons between the two adjacent atoms.

Here, Sodium is metal and fluorine is non-metal. So, the bond between them may be an ionic bond, but as the Sodium has one valence electron and fluorine is highly electronegative. Sodium wants to lose electrons and fluorine wants to gain electrons to form a chemical bond. Therefore, the sodium donates its valence electron to fluorine, forms a cation, and fluorine accepts the electron and forms an anion and they distribute the difference in the charge between them.

So, we can say that when sodium and fluorine react to form sodium fluoride with a covalent bond.

Learn more about covalent bonds here:

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4 0
2 years ago
The electron config for 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f14 5d10 6p3​
nadya68 [22]

Answer:

I don't understand what you are asking

3 0
3 years ago
What is the mass percentage of carbon in 5.000 G of sucrose
Crank
17) 8.4 / 20 x 100

18) 20 . 0.5150

19) 6,50% because (as you said) the law of definite proportions states that regardless of the amount, a compound is always composed of the same elements in the same proportion by mass
3 0
3 years ago
Read 2 more answers
What’s the frequency of radiation that has a wavelength of 13 um, about the size of bacterium?
choli [55]

Answer:

2.3)X10^13-Hz

Explanation:

What’s the frequency of radiation that has a wavelength of 13 um, about the size of bacterium?

a micro meter is 10^-6 meter

frequency of light times wavelength = c  the speed of light 3X10^8 M/sec

so

frequency times 13 X10^-6 =3X10^8  M/

so

FR3EQUENCY = 3X10^8/13X10-6

=(30/13)10^13 =2.3)X10^13-Hz

 

7 X

6

4 0
3 years ago
A chemistry student weighs out 0.09666 g of phosphoric acid (H3PO4), a triprotic acid, into a 250.volumetric flask and dilutes t
Ber [7]

Answer: 14.62 ml

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute  

V_s = volume of solution in ml = 250 ml

{\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{0.09666g}{98g/mol}=9.9\times 10^{-4}

Now put all the given values in the formula of molarity, we get

Molarity=\frac{9.9\times 10^{-4}\times 1000}{250ml}

Molarity=3.9\times 10^{-3}M

To calculate the volume of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_3PO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=3\\M_1=3.9\times 10^{-3}M\\V_1=250mL\\n_2=1\\M_2=0.2000M\\V_2=?

Putting values in above equation, we get:

3\times 3.9\times 10^{-3}\times 250=1\times 0.2000\times V_2\\\\V_2=14.62ml

Thus the volume of NaOH solution the student will need to add to reach the final equivalence point is 14.62 ml

8 0
3 years ago
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