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diamong [38]
3 years ago
9

A chemistry student is given the task of analyzing the three unknown samples in the previous question. Compare the densities fro

m Samples A, B, and C above to the accepted densities of the substances below. Identify the unknown samples as being either aluminum, iron, nickel, or tin. Densities of Common Elements Element Name Density (g/cm3) Aluminum 2.701 g/cm3 Iron 7.86 g/cm3 Nickel 8.90 g/cm3 Tin 7.28 g/cm3 Sample A ______________________ Sample B ______________________ Sample C _______________________
Chemistry
1 answer:
OLEGan [10]3 years ago
6 0

Answer:

It’s B

Explanation:

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Is pyrophoric a chemical or physical property
Neporo4naja [7]

Answer:

Pyrophoricity is a property of metals and oxides of lower oxidation states, including radioactive ones, in which they spontaneously ignite during or after stabilization.

5 0
3 years ago
X-rays have a wavelength small enough to image individual atoms, but are challenging to detect because of their typical frequenc
Cerrena [4.2K]

Explanation:

Given: \lambda = 8.38\:\text{nm} = 8.38×10^{-9}\:\text{m}

Its frequency \nu is defined as

\nu = \dfrac{c}{\lambda} = \dfrac{3×10^8\:\text{m/s}}{8.38×10^{-9}\:\text{m}}

\:\:\:\:= 3.58×10^{16}\:\text{Hz}

7 0
3 years ago
Ammonium nitrate, a common fertilizer, is used as an explosive in fireworks and by terrorists. It was the material used in the t
Sladkaya [172]

Explanation:

The given balanced reaction is as follows.

           2NH_{4}NO_{3} \rightarrow 2N_{2} + O_{2} + 4H_{2}O

It is given that mass of ammonium nitrate is 86.0 kg.

As 1 kg = 1000 g. So, 86.0 kg = 86000 g.

Hence, moles of NH_{4}NO_{3} present will be as follows.

      Moles of NH_{4}NO_{3} = \frac{mass given}{\text{molar mass of NH_{4}NO_{3}}}

                                  = \frac{86000 g}{80.043 g/mol}

                                  = 1074.42 mol

Therefore, moles of N_{2}, O_{2} and H_{2}O produced by 1074.42 mole of NH_{4}NO_{3} will be as follows.

  Moles of O_{2} = \frac{1}{2} \times 1074.42 mol

                                = 537.21 mol

Moles of N_{2} = \frac{2}{2} \times 1074.42 mol

                                = 1074.42 mol

Moles of H_{2}O = \frac{4}{2} \times 1074.42 mol

                                = 2148.84 mol

Therefore, total number of moles will be as follows.

          537.21 mol + 1074.42 mol + 2148.84 mol

        = 3760.47 mol

According to ideal gas equation, PV = nRT. Hence, calculate the volume as follows.

                       PV = nRT

                     1 atm \times V = 3760.47 mol \times 0.0821 L atm/mol K \times 580 K[/tex]         (as 307^{o}C = 307 + 273 = 580 K)

                           V = 179066.06 L

Thus, we can conclude that total volume of the gas is 179066.06 L.

3 0
3 years ago
Using the equation, 4Fe + 3O2 Imported Asset 2Fe2O3, if 111.6 g of iron react, what mass of oxygen was consumed?
Colt1911 [192]
Youll need a periodic table to get the masses
3 0
3 years ago
Read 2 more answers
This type of radiation is smallest and highest in energy
Pavel [41]

As your question is vague, I am assuming that you are talking Alpha, Beta and Gamma radiation. Out of these three radiation, Gamma radiation is the smallest in size compared to Alpha or Beta, but it has the highest energy levels. Gamma radiation is also known as photons. In other words, photons are light particles.

5 0
3 years ago
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