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diamong [38]
2 years ago
9

A chemistry student is given the task of analyzing the three unknown samples in the previous question. Compare the densities fro

m Samples A, B, and C above to the accepted densities of the substances below. Identify the unknown samples as being either aluminum, iron, nickel, or tin. Densities of Common Elements Element Name Density (g/cm3) Aluminum 2.701 g/cm3 Iron 7.86 g/cm3 Nickel 8.90 g/cm3 Tin 7.28 g/cm3 Sample A ______________________ Sample B ______________________ Sample C _______________________
Chemistry
1 answer:
OLEGan [10]2 years ago
6 0

Answer:

It’s B

Explanation:

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A.
Rus_ich [418]

Answer:

Multiple organisms may be affected by the loss of a plant species.

Explanation:

Organisms that feed directly off the lost plant will be affected, and because of that, organisms that feed off those organisms will be affected. This could also affect other organisms like parasites. Other plant species may be affected from the loss of a competitive species. This could affect organisms that feed off that plant, and the organisms that feed off those organisms.

6 0
2 years ago
Helppppp pls it’s due by today
Andrews [41]

Answer:

i can't see the picture

Explanation:

4 0
3 years ago
Read 2 more answers
A substance can change into a new kind of molecule when:
Artyom0805 [142]

Answer:

Chemical changes cause a substance to change into an entire substance with a new chemical formula. Chemical changes are also known as chemical reactions. The “ingredients” of a reaction are called reactants, and the results are called products.

Hope it helps

4 0
3 years ago
How many half-lives are required for the concentration of reactant to decrease to 1.56% of its original value?4247.56.56
neonofarm [45]

Answer:

6 half-lives are required for the concentration of reactant to decrease to 1.56% of its original value.

Explanation:

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given:

Concentration is decreased to 1.56 % which means that 0.0156 of [A_0] is decomposed. So,

\frac {[A_t]}{[A_0]} = 0.0156

Thus,

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.0156=e^{-k\times t}

kt = 4.1604

The expression for the half life is:-

Half life = 15.0 hours

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

\frac{4.1604}{t}=\frac {ln\ 2}{t_{1/2}}

t = 6\times t_{1/2}

<u>6 half-lives are required for the concentration of reactant to decrease to 1.56% of its original value.</u>

6 0
3 years ago
4.80 x 10^25 formula units pf calcium iodide (Cal2) will have what mass?
maw [93]

Answer:

mass CaI2 = 23.424 Kg

Explanation:

From the periodic table we obtain for CaI2:

⇒ molecular mass CaI2: 40.078  + ((2)(126.90)) = 293.878 g/mol

∴ mol CaI2 = (4.80 E25 units )×(mol/6.022 E23 units) = 79.708  mol CaI2

⇒ mass CaI2 = (79.708 mol CaI2)×(293.878 g/mol) = 23424.43 g

⇒ mass CaI2 = 23.424 Kg

7 0
3 years ago
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