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mars1129 [50]
3 years ago
8

how is rain, hail, and sleet similar and how are they different. Image of question attached. I really need help

Chemistry
1 answer:
maxonik [38]3 years ago
7 0
Its all water  and sleet and hail is ice 
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How many moles are in 213 grams of NaCl?
Nata [24]

Answer:

There are 3, 64 moles of NaCl.

Explanation:

First we calculate the mass of 1 mol of NaCl, starting from the atomic weights of Na and Cl obtained from the periodic table. Then we calculate themoles in 213 grams of NaCl, making a simple rule of three:

Weight NaCl= Weight Na + Weight Cl = 23 g + 35, 5 g= 58, 5 g/ mol

58,5 g ------1 mol NaCl

213 g---------x= (213 g x 1 mol NaCl)/ 58, 5 g= <em>3, 64 mol NaCl</em>

5 0
3 years ago
please hurry! If 3.87g of powdered aluminum oxide is placed in a container containing 5.67g of water, what is the limiting react
VikaD [51]

Answer:

Explanation:

Given parameters:

Mass of aluminium oxide = 3.87g

Mass of water = 5.67g

Unknown:

Limiting reactant = ?

Solution:

The limiting reactant is the reactant in short supply in a chemical reaction. We need to first write the chemical equation and convert the masses given to the number of moles.

Using the number of moles, we can ascertain the limiting reactants;

         Al₂O₃  + 3H₂O  →  2Al(OH)₃  

Number of moles;

            Number of moles = \frac{mass}{molar mass}

molar mass of Al₂O₃  = (2x27) + 3(16) = 102g/mole

    number of moles = \frac{3.87}{102}  = 0.04mole

   

molar mass of  H₂O = 2(1) + 16 = 18g/mole

    number of moles = \frac{5.67}{18}  = 0.32mole

From the reaction equation;

        1 mole of  Al₂O₃  reacted with 3 moles of H₂O

   0.04 mole of Al₂O₃ will react with 3 x 0.04 mole = 0.12 mole of H₂O

But we were given 0.32 mole of H₂O and this is in excess of amount required.

This shows that Al₂O₃ is the limiting reactant

           

6 0
2 years ago
Can you help me please, I’ll mark brainliest.
GrogVix [38]

Answer:

i think A

Explanation:

6 0
3 years ago
Can someone help me please
almond37 [142]

Answer:D

Explanation:

  1. Use the vertex form, y=a(x−h)2+ky=a(x-h)2+k, to determine the values of aa, hh, and kk.a=14a=14h=6h=6k=1k=1Find the vertex (h,k)(h,k).(6,1)(6,1)Find pp, the distance from the vertex to the focus.
  2. Find the distance from the vertex to a focus of the parabola by using the following formula.14a14aSubstitute the value of aa into the formula.14⋅1414⋅14Simplify.
  3. Combine 4 and 1/4 .1 /4/4
  4. Simplify by dividing numbers
  5. Divide 4 by 44.1/1Divide 1 by 1/1.
  6. Y=0
  7. The Answer is D
5 0
2 years ago
Oh no... not again... Prof. Vitarelli spots Sybil running down the hall... yelling something... something about her tea cups...
Y_Kistochka [10]

Answer:

The reducing agent is Zn.

Explanation:

Let's consider the reaction between zinc and hydrochloric acid.

Zn(s) + 2 HCl(aq) ⇄ ZnCl₂(aq) + H₂(g)

This is a redox reaction, which can be divided in 2 half-reactions: reduction and oxidation.

In the reduction, H⁺ gains electrons and it is considered the oxidizing agent.

2H⁺ + 2 e⁻ ⇒ H₂

In the oxidation, Zn loses electrons and it is considered the reducing agent.

Zn ⇒ Zn²⁺ + 2 e⁻

6 0
3 years ago
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