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3 years ago

Pls help :(

Chemistry

2 answers:

Ilia_Sergeevich [38]3 years ago

7 0

I would say only two

Pachacha [2.7K]3 years ago

5 0

$HEY THERE !!$

SULFUR has two unpaired atoms as SULFUR has 6 atoms total in which
Sulfur will have a pair of electrons in the 1st 3p orbital , 1 electron in the 2nd 3p orbital, and 1 electron in the 3rd 3p orbital.

S: 1s^22s^22p^63s^23p^4.

HOPE IT HELPED YOU.

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The question is missing parts. The complete question is as follows.

Consider the two gaseous equilibria involving SO2 and the corresponding equilibrium constants at 298K:

$SO_{2}_{(g)} + \frac{1}{2}O_{2}$ ⇔ $SO_{3}_{(g)}$ ; $K_{1}$

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The values of the equilibrium constants are related by:

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Answer: c) $K_{2} = \frac{1}{K_{1}^{2}}$

Explanation: Equilibrium constant is a value in which the rate of the reaction going towards the right is the same rate as the reaction going towards the left. It is represented by letter K and is calculated as:

$K=\frac{[products]^{n}}{[reagents]^{m}}$

The concentration of each product divided by the concentration of each reagent. The indices, m and n, represent the coefficient of each product and each reagent.

The equilibrium constants of each reaction are:

$SO_{2}_{(g)} + \frac{1}{2}O_{2}$ ⇔ $SO_{3}_{(g)}$

$K_{1}=\frac{[SO_{3}]}{[SO_{2}][O_{2}]^{1/2}}$

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Now, analysing each constant, it is easy to see that $K_{1}$ is the inverse of $K_{2}$ .

If you doubled the first reaction, it will have the same coefficients of the second reaction. Since coefficients are "transformed" in power for the constant, the relationship is:

$K_{2}=\frac{1}{K_{1}^{2}}$

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