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Oduvanchick [21]
3 years ago
15

Based on the information in the passage, what is true of gases?

Chemistry
1 answer:
luda_lava [24]3 years ago
7 0
1: True
2: True
3: False
4: False

(Question 2 might not be true, not sure)
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Describe what happens to the mass number and the atomic number of a nuclide during alpha decay.
Digiron [165]

Answer:

The answer to your question is: The mass number will be 4 units lower.

Explanation:

Alpha particles are Helium atoms, which have a mass number of 4 and atomic number of 2.

When an alpha particle is released, the original atom loses 2 protons and and 2 neutrons an we can see in the example.

                             ²²⁶ ₈₈ Ra  ⇒   ²²² ₈₆ Rn   +   ⁴₂ He

3 0
3 years ago
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An aqueous solution of potassium sulfate is allowed to react with an aqueous solution of calcium nitrate. identify the solid in
Maksim231197 [3]
Ans: Calcium sulfate.

K2SO4 (aq) + Ca(NO3)2 (aq) ⇒ 2KNO3 (aq) + CaSO4 (s)

6 0
3 years ago
Give the name of this alcohol.
solong [7]

Answer:

An alcohol is an organic compound with a hydroxyl (OH) functional group on an aliphatic carbon atom. Because OH is the functional group of all alcohols, we often represent alcohols by the general formula ROH, where R is an alkyl group. Alcohols are common in nature.

Explanation:

3 0
2 years ago
QUICK HELP PLEASE!!?? Need answer QUICK
d1i1m1o1n [39]

Answer:

B

Explanation:

Look on the x-axis for the tick marked "60". This indicates 60 degrees Celsius, which we want. Now, look on the y-axis for the tick marked "60". This indicates 60 grams of Na_2HAsO_4. Trace along the graph to find where these two places meet at (60, 60).

Now, look for the solubility curve of Na_2HAsO_4; it's the yellow-orange line. Find out what the y-coordinate of the point where x = 60 is on the line: it's around (60, 65).

So, since the point (60, 60) is below the line corresponding to this substance, Na_2HAsO_4 is unsaturated.

The answer is B.

4 0
3 years ago
Read 2 more answers
what is the percent by mass of NaHCO3 in a solution containing 20.0 g of NaHCO3 dissolved in 600.0 ml of water
Ne4ueva [31]
%(NaHCO3)= ((mass NaHCO3)/(mass NaHCO3 + mass water))*100%

m=Volume*Density
Density of water =1 g/ml
m(water) = Volume(water)*Density(water) = 600.0 ml * 1g/ml=600g water

%(NaHCO3)= ((20.0 g)/(20.0 g + 600 g))*100%=0.0323*100%=32.3%
7 0
3 years ago
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