Answer:
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Step-by-step explanation:
Answer:
63%
Step-by-step explanation:
<em>From the question, we aim to find the percent increase in the tuition</em>
Given data
initial cost= $99 per credit hour
Final cost= $268 per credit hour
% increase= (Final - initial )/initial *100
substitute
% increase= (268- 99 )/268 *100
% increase= 169 /268 *100
% increase= 0.630*100
% increase= 63%
Hence the increase in the tuition from 1990 to 2003 is 63%
The stock price per share was $8.60
Number of shares bought 1000
Total price for the shares:
(Cost per share)*(Number of shares)
=8.60*1000
=$8600
The stock price after 1 year $9.15
Total number of shares is 1000
Current price=(current share price)*(number of shares)
9.15*1000
=$9150
current value=(Current price)-(buying price)
=9150-8600
=$550
Net Profit=(Current value)-(Expenses)
=550-14
=$536
we are given
62% of the students take math
so,

49% take science

38% take both science and math
n(M∩S)=38
now, we can use union formula
n(M∪S)=n(M)+n(S) -n(M∩S)
now, we can plug values
and we get
n(M∪S)=62+49 -38
n(M∪S)=73
so,
the percentage takes at least one science or math course is 73%..........Answer