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lozanna [386]
3 years ago
15

A laser with wavelength d/8 is shining light on a double slit with slit separation 0.300 mm. This results in an interference pat

tern on a screen a distance away from the slits. We wish to shine a second laser, with a different wavelength, through the same slits.
(a) What is the wavelength of the second laser that would place its second maximum at the same location as the fourth minimum of the first laser, if d = 0.300 mm?
Physics
1 answer:
AlexFokin [52]3 years ago
7 0

Answer:

0.066mm

Explanation:

let wavelength be λ

1st laser

fourth minima occurs at a distance of 7λa/2d

which is equal to 7a/16 as λ = d/8

now for 2nd laser

let wavelength be λ'

second maxima occurs at a distance of 2λ'a/d

so 7a/16 = 2λ'a/d

∴ λ' = 7d/32 = 0.066 mm

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When a gas is rapidly compressed (say, by pushing down a piston) its temperature increases. When a gas expands against a piston,
shusha [124]

Answer:

Explained in explanation

Explanation:

The first law of thermodynamics states that the change in internal energy of a system(ΔU) is equal to the sum of the net heat transfer into the system(Q) and the net work done on the system(W). In equation, this law is;

ΔU = Q + W

Now, when there's gas inside a container with a movable piston that's tightly fitting, we will assume that the piston can move up and down thereby compressing the gas or allowing the gas to expand against it.

Now these gas molecules inside the container possess kinetic energy. Thus, the internal energy(U) of the system is simply the sum of all the kinetic energies of the individual gas molecules present in the container.

Therefore, if the temperature(T) of the gas increases, then the speed and internal energy(U) of the gas molecules will also increase. In the same way, if the temperature of the gas decreases, the speed and internal energy of the gas molecules would also decrease.

Now, back to the question, when the piston is pushed down, it does work on the gas and the gas does negative work on the piston. Thus, the gas will be get compressed to a smaller space, and thereby making the gas molecules to hit the piston at a faster rate. Thus, there is a decrease in speed and as we saw earlier that when there is a decrease in speed, it means temperature has decreased.

Whereas, when the piston is moved up, the gas does positive work on the piston and the speed of the gas molecules will increase. Like I said earlier that increase in speed means increase in temperature.

4 0
3 years ago
A 0.0100 kg ice cube at 0 degree C is melted, warmed to 100 degree C, then boiled off. How much heat did the water absorb
AfilCa [17]

Answer:30116

Explanation:

5 0
3 years ago
In a simplified model of a hydrogen atom, the electron moves around the proton nucleus in a circular orbit of radius 0.53×10−10m
Ksenya-84 [330]

Answer

given,

radius of the circular orbit, r = 0.53 x 10⁻¹⁰ m

mass of electron, M = 9.11 x 10⁻³¹ Kg

charge of electron, q₁ = 1.6 x 10⁻¹⁹ C

                                q₂ = 1.6 x 10⁻¹⁹ C

we know, force between two charges

F = \dfrac{kq_1q_2}{r^2}

F = \dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{(0.53\times 10^{-10})^2}

  F = 8.20 x 10⁻⁸ N

b) using newton's second law

F = m a

m a =  8.20 x 10⁻⁸

a =\dfrac{8.20\times 10^{-8}}{9.11\times 10^{-31}}

    a = 9 x 10²² m/s²

c) speed of the electron

 a =\dfrac{v^2}{r}

 9\times 10^{22} =\dfrac{v^2}{0.53\times 10^{-10}}

   v² = 4.77 x 10¹²

  v = 2.18 x 10⁶ m/s

d) the period of the circular motion.

    T=\dfrac{2\pi}{\omega}

    T=\dfrac{2\pi r}{v}

    T=\dfrac{2\pi\times 0.53\times 10^{-10}}{2.18\times 10^6}

          T = 1.53 x 10⁻¹⁶ s

8 0
3 years ago
Read 2 more answers
An object 82 cm high forms a virtual image 4.1 cm high located 4.6 cm behind a mirror. Find the object distance.
ioda

Answer:

The object distance is 92 cm.  

Explanation:

let v be the image distance and h be the height of the image, let u the be the object distance and H be the height of the object.

then, the magification of the mirror is given by:

m = -v/u and m = h/H

so, -v/u = h/H

         u = -v×H/h

            = -(-4.6)×(82)/(4.1)

            = 92 cm

Therefore, the object distance is 92 cm.

8 0
3 years ago
1. If the angle of the ramp were increased from 30˙ to 45˙, how would this change the weight of the box? Explain.
yawa3891 [41]

When the angle of the ramp increases, the weight of the box acting perpendicular to the ramp decreases.

<h3>Normal reaction of the box</h3>

The normal reaction of the box is due to weight of the box acting perpendicular to the ramp.

Fn = Wcosθ

<h3>when the angle of the ramp = 30⁰</h3>

Fn = Wcos(30)

Fn = 0.866W

<h3>when the angle of the ramp = 45⁰</h3>

Fn = W x cos(45)

Fn = 0.7071W

Thus, when the angle of the ramp increases, the weight of the box acting perpendicular to the ramp decreases.

Learn more about normal reaction here: brainly.com/question/18292235

#SPJ1

4 0
2 years ago
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