The result would be: loss of farmland
<span>In the cytoplasm, ribsomal RNA (rRNA), a type of RNA, and
protein combine to form a nucleoprotein called a ribosome. The ribosome
serves as the site and carries the enzymes necessary for protein
synthesis. They are often takes the shape of small round particles
attached in the endoplasmic reticulum. The ribosome attaches itself to m-RNA
and provides the stabilizing structure to hold all substances in position as
the protein is synthesized. Several ribosomes may be attached to a single RNA
at any time. <span> </span></span>
Answer:
The volume of the neon gas is 17.07 L.
Explanation:
The ideal gas equation describes the relationship among the four variables P, V, T, and n. An ideal gas<u> is a hypothetical gas whose pressure-volume-temperature behavior can be completely accounted for by the ideal gas equation</u>.
In order to calculate the volume, first we need to convert the grams of neon to moles:
28.18 g Ne ------ 1 mol Ne
5.0 g Ne---------- <u>x= 0.25 mol Ne</u>
Now, using the ideal gas equation we calculate the volume:
V= 17.07 L
Answer:
Detail is given below
Explanation:
Atomic radii trend along group:
As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.
As the size of atom increases the ionization energy from top to bottom also decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.
In A we can see that there is one positive charge and force of attraction is 2.30×10⁻⁸ N and distance is 0.10 nm
In B we can see that negative charge is further away from nucleus because of greater distance thus force of attraction will be less. 0.58×10⁻⁸ N
In C this distance further increases and force also goes in decreasing 0.26×10⁻⁸ N.
I think you mean:
".. reacts with oxygen gas to produce lead (II) oxide and 'sulfur' dioxide..."
The balanced chemical reaction would be
2PbS + 3O2 --> 2PbO + 2SO2
The stiochiometric ratio is this: 3 moles of O2 produces 2 moles of lead (II) oxide. So,
0.500 moles (2/3) = 0.333 moles
Therefore, 0.333 moles of PbO is produced when 0.500 moles of O2 reacts with PbS.
