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solong [7]
3 years ago
8

We repeat the experiment from the video, but this time we connect the wires in parallel rather than in series. Which wire will n

ow dissipate the most heat?
Physics
1 answer:
Lady bird [3.3K]3 years ago
5 0

Answer:

Explanation:

The wire which is connected in series will dissipate the most heat.

The reason behind this fact is that, for the wire connected in series, there is only one path for the flow of electrons that's why electron face more opposition and thus more heat dissipation. However, in parallel connecting wires, alternate paths are available for the flow of electrons. That's why the electrons do not face that much opposition as in series case as the path and the flow is divided.

You can understand this concept by the example of traffic on the roads. If there is a single road, then you have to face the more opposition and you will have the less passage to drive through. However if there are parallel roads, then the traffic will got more space to move. It will become easier for them and opposition will be reduced. Hope you understand it :)

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The four giant gas planets that are made primarily of lightweight elements are
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D) although recent research (1990's) has shown Uranus and Neptune to be ice giants and have heavier substances.
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3 years ago
A small logo is embedded in a thick block of crown glass (n = 1.52), 4.70 cm beneath the top surface of the glass. The block is
harkovskaia [24]

The concept required to solve this problem is the optical relationship that exists between the apparent depth and actual or actual depth. This is mathematically expressed under the equations.

d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})

Where,

d_g = Depth of glass

n_w = Refraction index of water

n_g = Refraction index of glass

n_{air} = Refraction index of air

d_w = Depth of water

I enclose a diagram for a better understanding of the problem, in this way we can determine that the apparent depth in the water of the logo would be subject to

d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})

d'w = (1.7cm) (\frac{1}{1.33})+(4.2cm)(\frac{1}{1.52})

d'w = 4.041cm

Therefore the distance below the upper surface of the water that appears to be the logo is 4.041cm

3 0
3 years ago
The Statue of Liberty weighs nearly 205 metric tons. If a person can pull an average of 90 kg, how many people would it take to
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A car is traveling up a hill that is inclined at an angle θ above the horizontal. Determine the ratio of the magnitude of the no
padilas [110]

Explanation:

The weight of the car is equal to, W_c=m\times g...........(1)

Where

m is the mass of car

g is the acceleration due to gravity

The normal or vertical component of the force is, F_N=mg\ cos\theta

or

F_N=mg\ cos(13).............(2)

The horizontal component of the force is, F_H=mg\ sin\theta

Taking ratio of equation (1) and (2) as :

\dfrac{F_N}{W_c}=\dfrac{mg\ cos\theta}{mg}

\dfrac{F_N}{W_c}=cos(13)

\dfrac{F_N}{W_c}=0.97

or

\dfrac{F_N}{W_c}=\dfrac{97}{100}

Hence, this is the required solution.

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3 years ago
C, N, Ne, Ar which contains a metal, nonmetal, noble gas , metalloid
postnew [5]

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c,carbono nonmetal

n, nitrogen nonmetal

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ar,argon noble gas

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