Answer:
People are exposed to sources of radiation in all aspects of everyday life. Radioactive sources can be very useful but need handling carefully to ensure safety.
Explanation:
Answer: 1.While the ball is not in contact with the ground, the height at time t after the last bounce at t0 is given by h(t+t0)=v0t−12gt2. where v0 is the velocity just after the bounce. 2.During the impact, the ball will deform and there will be friction.
My estimate is 1/2 inch per week.
(0.5 inch/wk) x (1 wk / 7 da) x (1 da / 86,400 sec) x (1 meter / 39.37 inches)
= (0.5 x 1 x 1 x 1) / (7 x 86,400 x 39.37) meter/second
= 1 / 47,621,952 meter/second
= 0.0000000209987... m/s
= 2.1 x 10⁻⁸ meter/second
= 2.1 x 10⁻⁵ mm/sec
= 0.000021 millimeter per second (rounded)
Answer:
the electric charge in the Earth is -5.91 × 10⁵ C
Explanation:
Given the data in the question;
Electric field E = 131 N/C
we know that; radius of the earth r = 6,371 km = 6371000 m
and Coulomb's constant k = 8.99 × 10⁹ Nm²/c²
Now, using the following formula to calculate the charge;
E = k × Q/r²
we make Q the subject of the formula
Q = Er² / k
so we substitute
Q = [ 131 N/C × ( 6371000 m )² ] / 8.99 × 10⁹ Nm²/c²
Q = [ 5.317242971 × 10¹⁵ ] / [ 8.99 × 10⁹ ]
Q = 5.91 × 10⁵ C
Since the electric field pointing downward
Q = -5.91 × 10⁵ C
Therefore, the electric charge in the Earth is -5.91 × 10⁵ C