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<h2>It will take 0.125 seconds to reach the net.</h2>
Explanation:
Initial speed, u = 34 ft/s = 10.36 m/s
Acceleration, a = -9.81 m/s²
Displacement, s = Final height - Initial height = 8 - 4 = 4 ft = 1.22 m
We have equation of motion, s = ut + 0.5 at²
Substituting
s = ut + 0.5 at²
1.22 = 10.36 x t + 0.5 x -9.81 x t²
4.905t² - 10.36 t + 1.22 = 0
t = 1.99 s or t = 0.125 seconds
Minimum time is 0.125 seconds.
It will take 0.125 seconds to reach the net.
Answer:
Work done on the car will be 548440.9463 J
Explanation:
We have given mass of the car m = 1075 kg
As the car finally stops so final velocity of the car
Initial velocity of car u = 115 km/hr
Work done is equal to change in kinetic energy
So work done
=
As the work done is negative so work is done on the car to stop it .