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JulsSmile [24]
3 years ago
6

A force of 3,200 kg x m/s^2 (Newton’s) acts on a truck giving it an acceleration of 2 m/s^2. What is the mass of the truck ?

Physics
1 answer:
Ivan3 years ago
3 0

Answer:

According to newton's second law of motionF=ma Data:-F=3200kgm/sec² or N ,a=2m/sec² ,m=? solution :-F=ma here we have to find m so m=F/a ,m=3200/2=1600kg

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If a proton and an electron are released when they are 7.00×10−10 m apart (typical atomic distances), find the initial accelerat
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Answer:

The acceleration of the proton is 2.823 x 10¹⁷ m/s²

The acceleration of the electron is 5.175 x 10²⁰ m/s²

Explanation:

Given;

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mass of proton, m_p = 1.67 x 10⁻²⁷ kg

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The attractive force between the two charges is given by Coulomb's law;

F = \frac{k(q_p)(q_e)}{r^2}

where;

k is Coulomb's constant = 9 x 10⁹ Nm²/c²

F = \frac{k(q_p)(q_e)}{r^2} \\\\F = \frac{(9*10^9)(1.602*10^{-19})(1.602*10^{-19})}{(7*10^{-10})^2} \\\\F = 4.714 *10^{-10} \ N

Acceleration of proton is given by;

F = ma

F = m_pa_p\\\\a_p = \frac{F}{m_p}\\\\a_p = \frac{4.714*10^{-10}}{1.67*10^{-27}}\\\\a_p = 2.823 *10^{17} \ m/s^2

Acceleration of the electron is given by;

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7 0
3 years ago
Assume that two of the electrons at the negative terminal have attached themselves to a nearby neutral atom. There is now a nega
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Answer: its negative

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