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arlik [135]
3 years ago
11

Is 1000g same as 1cm3

Chemistry
1 answer:
brilliants [131]3 years ago
7 0
1cm3=1mL=1cc 
1000g=1Kg
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Consider the change given below. At constant pressure, is work done by the system on the surroundings? By the surroundings on th
alexira [117]

Answer : At constant pressure work is done by the system on the surroundings.

Explanation :

Work done : Any quantity that flows across the boundary of a system during a change in its state and it completely convertible into the lifting of a weight in the surroundings.

Formula for work done is:

w=-p_{ext}dV

Sign convention :

  • When volume expand then system work that means work done by the system.

w = (-ve)

  • When volume compress then surrounding work that means work done on the system.

w = (+ve)

The given reaction is:

Hg(l)\rightarrow Hg(g)

This is a evaporation process in which phase changes from liquid state to gaseous state at constant temperature.

At constant pressure, work depends only on volume.

In evaporation process, the volume expand that means work is done by the system on the surroundings.

Sign convention is, w = (-ve)

Thus, at constant pressure work is done by the system on the surroundings.

7 0
3 years ago
When naming ionic compounds the ______________ is named first.
grandymaker [24]
The answer is metal. Metals are always named first in ionic compounds, like KNO3 for example. I hope this helps!
7 0
3 years ago
1.
dolphi86 [110]

Answer: D. transverse

Explanation:

Light is a transverse wave, while sound is a longitudinal wave.

8 0
2 years ago
What is the solubility of NH4Cl at 50°C?
astra-53 [7]

The correct answer is E. 50 grams

The solubility of Ammonium Chloride has an increasing trend as the temperature increases. Experiments show that the solubility at 323K is approximately 50.4 grams per 100 grams o water thus this value is close to choice D, 50 grams

8 0
3 years ago
Read 2 more answers
Calculate the pH of a buffer solution prepared by dissolving 0.20 mole of cyanic acid (HCNO) and 0.80 mole of sodium cyanate (Na
Afina-wow [57]

The pH of a buffer solution : 4.3

<h3>Further explanation</h3>

Given

0.2 mole HCNO

0.8 mole NaCNO

1 L solution

Required

pH buffer

Solution

Acid buffer solutions consist of weak acids HCNO and their salts NaCNO.

\tt \displaystyle [H^+]=Ka\times\frac{mole\:weak\:acid}{mole\:salt\times valence}

valence according to the amount of salt anion  

Input the value :

\tt \displaystyle [H^+]=2.10^{-4}\times\frac{0.2}{0.8\times 1}\\\\(H^+]=5\times 10^{-5}\\\\pH=5-log~5\\\\pH=4.3

7 0
3 years ago
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