Bromine has 35 protons, and in this case 46 neutrons, so 35 + 46 = 81
Therefore, the symbol is (subscript 35)(superscript 81) Br.
Answer:
C: electrons is the 3s orbital are higher than those in the 2s orbital
Explanation:
Looking at the options, the correct one is that the electrons in the 3s orbital will possess more energy than those in the 2s orbital. This is because the the 2s orbitals will be filled with electrons first before the 3s orbital.
Also from basics we know that the energy of an orbital increases as the quantum number increases.
Answer:
Compound formula : HCl
Element H
# atoms:1
Elements Cl
#atoms : 1
gram formula weight (g) = 36.46
Answer:
1.070MKCl
Explanation:
So we know that the original formula is M= n/L (n being moles of solute, L being liters of solvent)
Since we do not have liters in this problem, we would need to convert milliliters to liters
<u>213 mL= 0.213 L</u>
We then see that we do not have moles, but we do have a mass, being <u>17.0 g.</u> we would need to convert these grams to moles, giving us <u>0.228 mol.</u>
Then, you would plug in <u>0.228 for your n</u>, and now you are ready to solve your original formula, plugging everything in.
M=n/L
M=0.228 mol/0.213L
M= 1.070MKCl
I know this was long, but I hope this helps (:
Answer:
<em>Correct answer-C 5.3g</em>
Explanation:
M<em><u>olarity = no. of moles of solute/ volume of of solution in litre</u></em>
<em><u>olarity = no. of moles of solute/ volume of of solution in litreno of moles of solute = 0.125×0.25=0.03125</u></em>
<em><u>olarity = no. of moles of solute/ volume of of solution in litreno of moles of solute = 0.125×0.25=0.03125one mole AgNO3 weighs 169.87 gm,</u></em>
<em><u>olarity = no. of moles of solute/ volume of of solution in litreno of moles of solute = 0.125×0.25=0.03125one mole AgNO3 weighs 169.87 gm,so the mass of 0.03125 moles of AgNO3 = 0.03125×169.87= </u></em><em><u>5.3084g</u></em>
