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lord [1]
4 years ago
6

C) If 0.66 mole of iron (III) oxide were produced from the reaction, that must mean that how many mole

Chemistry
2 answers:
Fudgin [204]4 years ago
4 0

Answer:

If there is 0.66 moles of iron(III)oxide produced, there reacte 0.99 moles of oxygen (O2)

Explanation:

Step 1: Data given

Number of moles iron (III) oxide (Fe2O3) = 0.66 moles

Step 2: The balanced equation

4Fe + 3O2 → 2Fe2O3

Step 3: Calculate moles of oxygen (O2)

For 4 moles Fe consumed, we need 3 moles of O2 to produce 2 moles of Fe2O3

For 0.66 moles Fe2O3 produced, we need 3/2 * 0.66 = 0.99 moles of O2

If there is 0.66 moles of iron(III)oxide produced, there reacte 0.99 moles of oxygen (O2)

Margarita [4]4 years ago
4 0

Answer:

0.99 moles of O₂

Explanation:

Let's consider the reaction between iron and oxygen to produce iron (III) oxide.

4 Fe + 3 O₂ → 2 Fe₂O₃

The molar ratio of oxygen to iron (III) oxide is 3:2. The moles of oxygen that reacted to form 0.66 moles of iron (III) oxide are:

0.66 mol Fe₂O₃ × (3 mol O₂/2 mol Fe₂O₃) = 0.99 mol O₂

0.99 moles of O₂ reacted to produce 0.66 moles of Fe₂O₃.

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A thermite reaction realeses large amounts of heat and light resulting in the melting of the iron metal
lara [203]

Answer:

1. Fe₂O₃ : Al = 1 : 2

2. Fe₂O₃ : Al₂O₃ = 1 : 1

3. Fe₂O₃ : Fe = 1 : 2

Note: The question is incomplete. The complete question is given below :

A thermite reaction releases large amounts of heat and light, resulting in the melting of the iron metal that forms during the reaction. The balanced chemical equation is given below: Fe₂O₃(s) + 2Al(s) ---> Al₂O₃(s) + 2Fe(l) Determine the correct mole ratios for the following substances, based on this chemical equation.

Explanation:

A thermite reaction is a highly exothermic reaction that occurs between a mixture of powdered aluminium and iron (iii) oxide.

The reaction is a redox reaction which produces aluminium oxide and metallic iron.

The heat given out in the reaction melts the iron formed. It is used to join railway tracks or cracked machine parts. The molten iron runs down between the tracks and welds them together.

The balanced equation of the reaction is given below :

Fe₂O₃(s) + 2Al(s) ---> Al₂O₃(s) + 2Fe(l) + Heat

The mole ratio of the reactant and products are as follows:

1. 1 mole of Iron (iii) oxide and 2 moles of aluminium are combined

Fe₂O₃ : Al = 1 : 2

2. 1 mole of aluminium oxide is produced from 1 mole of iron (iii) oxide

Fe₂O₃ : Al₂O₃ = 1 : 1

3. 2 moles of of iron are produced from 1 mole of iron (iii) oxide

Fe₂O₃ : Fe = 1 : 2

4 0
3 years ago
The complete combustion of copper(I) sulphide is according to the following equation:
MaRussiya [10]

Answer:

a) 7.94 x 10²³ molecules, b) 5.62 g SO2, c) 1.97 L

Explanation:

a) We need to first convert Cu2S to moles. Since molar mass of Cu2S is 159.14 g/mol, 14.0 g = 0.0880 mol. Using molar ratios (3 mol O2/2 mol Cu2S, 0.0880 mol of Cu2S = 0.132 mol O2. Since 1 mol contains 6.02 x 10²³ molecules, 0.132 mol O2 = 7.94 x 10²² molecules O2.

b) Since the molar ratios of Cu2S to SO2 is 1:1, 0.0880 mol of Cu2S produces 0.0880 mol SO2. To convert mol to grams, we use the molar mass of SO2 (64.06 g/mol) to figure out that 0.0880 mol SO2 = 5.63 g SO2.

c) At STP, 1 mol occupies 22.4 liters. 0.0880 mol SO2 x 22.4 L/1 mol = 1.97 L

If you would like more tutoring in chemistry or other subjects for FREE, check out growthinyouth.org.

5 0
3 years ago
If chemical weathering occurs when minerals inside of the rock changes chemically. Will it change the rate of chemical weatherin
Mariulka [41]
Increase of rainfall will accelerate chemical weathering. Especially if the runoff is slightly acidic.
7 0
3 years ago
What is the net ionic equation for the precipitation reaction between BaCl2 and Na2SO4?
Tom [10]
BaCl2 + Na2SO4-----> 2NaCl + BaSO4(s)

net ionic equation- Ba+2 + SO4 -2 -----> BaSO4 (s)
8 0
3 years ago
If 11.00 mL of a standard 0.2831 M NaOH solution is required to neutralize 26.86 mL of H2SO4, what is the molarity of the acid s
MrRa [10]

Answer:

0.1159 M

Explanation:

Using the formula below:

CaVa = CbVb

Where;

Ca = concentration/molarity of acid (M)

Cb = concentration/molarity of base (M)

Va = Volume of acid (mL)

Vb = volume of base (mL)

According to this question, the following information were given:

Ca = ?

Cb = 0.2831 M

Va = 26.86 mL

Vb = 11.00 mL

Using CaVa = CbVb

Ca × 26.86 = 0.2831 × 11

26.86Ca = 3.1141

Ca = 3.1141 ÷ 26.86

Ca = 0.1159

The molarity of the acid (H2SO4) solution is 0.1159 M

3 0
3 years ago
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