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lord [1]
3 years ago
6

C) If 0.66 mole of iron (III) oxide were produced from the reaction, that must mean that how many mole

Chemistry
2 answers:
Fudgin [204]3 years ago
4 0

Answer:

If there is 0.66 moles of iron(III)oxide produced, there reacte 0.99 moles of oxygen (O2)

Explanation:

Step 1: Data given

Number of moles iron (III) oxide (Fe2O3) = 0.66 moles

Step 2: The balanced equation

4Fe + 3O2 → 2Fe2O3

Step 3: Calculate moles of oxygen (O2)

For 4 moles Fe consumed, we need 3 moles of O2 to produce 2 moles of Fe2O3

For 0.66 moles Fe2O3 produced, we need 3/2 * 0.66 = 0.99 moles of O2

If there is 0.66 moles of iron(III)oxide produced, there reacte 0.99 moles of oxygen (O2)

Margarita [4]3 years ago
4 0

Answer:

0.99 moles of O₂

Explanation:

Let's consider the reaction between iron and oxygen to produce iron (III) oxide.

4 Fe + 3 O₂ → 2 Fe₂O₃

The molar ratio of oxygen to iron (III) oxide is 3:2. The moles of oxygen that reacted to form 0.66 moles of iron (III) oxide are:

0.66 mol Fe₂O₃ × (3 mol O₂/2 mol Fe₂O₃) = 0.99 mol O₂

0.99 moles of O₂ reacted to produce 0.66 moles of Fe₂O₃.

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Stearic acid (C18H36O2) is a fatty acid, a molecule with a long hydrocarbon chain and an organic acid group (COOH) at the end. I
Paha777 [63]

Answer:

There is 9671  Kj of heat released

Explanation:

<u>Step 1:</u> The balanced equation:

C18H36O2(s) + 26O2(g) --> 18CO2(g)+18H2O(g)

This means for 1 mole of C18H36O2 consumed there is 26 moles of O2 needed to produce 18 moles of CO2 and 18 moles of H2O.

<u>Step 2:</u> Calculate the heat of combustion

ΔH (combustion) = [18*(ΔHf of CO2) + 18*(ΔHf of H2O)] - [1*(ΔHf of C18H36O2) + 26*(ΔHf of O2)]

ΔH (combustion) = [18*(-394 kJ/mol) + 18*(-242 kJ/mol)] - [1*(-948 kJ/mol) + 26*(0 kJ/mol)]

ΔH (combustion) = [(-7092 kJ/mol) + (-4356 kJ/mol)] - (-948 kJ/mol)

= -10500 kJ/mol

ΔH (combustion) = heat released / number of moles of stearic acid

<u>Step 3:</u> Calculate moles of stearic acid

moles of stearic acid = mass / Molar mass of stearic acid

moles of stearic acid = 262g / 284.48 g/mole = 0.921 moles

<u>Step 4:</u> Calculate moles of oxygen

moles of O2 = 914.5 / 32g/mole

moles of O2 = 28.578125 moles

Stearic acid is the limiting reactant: it will <u>completely react</u>

There will react 26*0.921 mole = 23.946 mole of O2

This means there will remain 4.63 moles of O2

<u>Step 5:</u> Calculate heat released

q = (ΔH combustion) * (moles of stearic acid) = (-10500 kJ/mol) * (0.921 moles) = 9671 Kj

There is 9671  Kj of heat released

6 0
2 years ago
What is a mol in chemistry
Snowcat [4.5K]
Molecular weight it stands for molecular weight






6 0
3 years ago
If an atom with a mass number of 27 has 14 neutrons,it is an isotope of which element​
kkurt [141]

Answer:

the number of neutrons in above isotope = A - Z = 27 - 13 = 14. Note: The molar mass of aluminium, which is average of atomic masses of all isotopes = 26.981538 g/mol, since 13Al27 is the major isotope.

Explanation:

   

5 0
3 years ago
Read 2 more answers
Which statements are true concerning elements in the same group of the periodic table? Select all that apply.
Tatiana [17]

The statements A and F are true concerning elements in the same group of the periodic table.  

To select all that apply, we need to evaluate each statement.

A. They have similar periodic properties.  

This statement is true. All the elements in the same group will have similar chemical and physical properties due to the electron configuration of their outer shell. For example, the alkali metals group (Li, Na, K, Rb, Cs, and Fr), has a valence electron configuration of s¹ (in the outer shell), which gives them the tendency to react vigorously with water, as well as other properties.      

B. They are all metals or nonmetals, but not both.

This is false. If we take a look at the p-block of the periodic table, we can see that the <u>groups</u> in this block are conformed by nonmetals, metals, and metalloids. For example, the icosagens group is formed by metalloids (B) and metals (Al, Ga, In, Tl).          

 

C. They are either all solids or all liquids or all gases.

This is false. In some groups, all the elements are solids (alkaline earth metals) or gases (group of noble gases), but in others, the groups are conformed by gases with solids (pnictogens group) or by gases with liquids (halogens group).  

   

D. They have the same number of shells of electrons.

This is false. In a group, the number of shells <u>increases from top to bottom</u> in the periodic table. For example, the electron configuration of the elements in the alkali metals is:        

  • H: 1s¹      
  • Li: [He]2s¹
  • Na: [Ne]3s¹
  • K: [Ar]4s¹
  • Rb: [Kr]5s¹
  • Cs:  [Xe]6s¹
  • Fr: [Rn]7s¹

We can see that hydrogen has 1 shell and Cs has 6 shells.  

E. They have the same number of inner core electrons.

This is false. As we said at point D, the number of shells increases from top to bottom in a group, so the number of inner core electrons also increases in this order. For example, in the alkaline earth metals group, the electron configuration of the elements is:  

  • Be: [He]2s²
  • Mg: [Ne]3s²
  • Ca: [Ar]4s²
  • Sr: [Kr]5s²
  • Ba: [Xe]6s²
  • Ra: [Rn]7s²

As we can see, the number of inner shells increases from Be ([He]) to Ra ([Rn]).    

F. They have the same outer shell electron configuration.

This is true. As we said at point A, the elements in the same group will have the same electron configuration of the outer shell (valence electron configuration). At points D and E, we can see that the valence electron configuration is the same for all the elements in the groups.    

Therefore, statements A and F are true.      

You can find more about the periodic table here: brainly.com/question/4287157?referrer=searchResults

I hope it helps you!    

           

6 0
3 years ago
If Matteo has a model car with a volume of 100 mL and a mass of 200 g, what is the density of their model car?
OLEGan [10]

Answer:

<h2>2 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question we have

density =  \frac{200}{100}  \\

We have the final answer as

<h3>2 g/mL</h3>

Hope this helps you

6 0
2 years ago
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