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Katen [24]
3 years ago
11

Under certain conditions neon gases diffuse at a rate of 7.0 cm/s under the same conditions as an on known gas defuses at a rate

of 4.9 Per second what is the approximate molar mass of the unknown gas?
Chemistry
1 answer:
Norma-Jean [14]3 years ago
6 0
Answer : To find the molar mass of unknown gas we need to solve the equation of rate of diffusion and molecular weight of the gases, which is as follows;

\frac{rate of diffusion of gas A X  \sqrt{mol wt of gas B} }{rate of diffusion of gas B X  \sqrt{mol wt of gas A} } =1

here the mol wt of gas B is not known so we take it as '<em>x'

</em>on solving we get 7 X \sqrt{x} / 4.9 X \sqrt{41}
<em>
</em>mol. wt of unknown gas = 20.0 g
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liq [111]
<h2>Answer</h2>

The volume will be<u> 50 L</u>

<h2>Explanation</h2>

From Kelvin Law of Temperature, we know that

V_{1} T_{1} =V_{2} T_{2}

We know that

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So,

V_{2} = V_{1} T_{1}/T_{2}

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The answer of the givern question is 50L


5 0
3 years ago
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Answer:

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Explanation:

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4 0
3 years ago
Why do you need many different indicators to span the entire ph spectrum?
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3 years ago
A sample of helium gas is placed in a rigid cylinder that has a movable piston. The volume of the gas is varied by moving the pi
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The equation for the combustion of CH4 (the main component of natural gas) is
Lera25 [3.4K]

Heat produced =  -13588.956 kJ

<h3>Further explanation</h3>

Given

The reaction of combustion of Methane

CH4(g)+2O2(g)→CO2(g)+2H2O(g) ΔH∘rxn=−802.3kJ

271 g of CH4

Required

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mol of 271 g CH₄ (MW=16 g/mol0

mol = mass : MW

mol = 271 : 16

mol = 16.9375

So Heat produced :

= mol x ΔH°rxn

= 16.9375 mol x −802.3kJ/mol = -13588.956 kJ

6 0
3 years ago
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