Answer:
Tarzan, who weighs 688N, swings from a cliff at the end of a convenient vine that is 18m long. From the top of the cliff to the bottom of the swing he descends by 3.2m.
Explanation:
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The kinematics for the vertical launch we can enter the initial velocity is 11.76 m / s
Given parameters
To find
Kinematics is the part of physics that establishes the relationships between the position, velocity, and acceleration of bodies.
In this case we have a vertical launch
y = y₀ + v₀ t - ½ g t²
Where y and y₀ are the final and initial positions, respectively, v₀ the initial velocity, g the acceleration of gravity (g = 9.8 m / s²) and t the time
With the ball in hand, its position is zero
0 = 0 + v₀ t - ½ g t²
v₀ t - ½ g t² = 0
v₀ = ½ g t
Let's calculate
v₀ = ½ 9.8 2.4
v₀ = 11.76 m / s
In conclusion using kinematics for the vertical launch we can enter the initial velocity is 11.76 m / s
Learn more about vertical launch kinematics here:
brainly.com/question/15068914
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Answer: 996m/s
Explanation:
Formula for calculating velocity of wave in a stretched string is
V = √T/M where;
V is the velocity of wave
T is tension
M is the mass per unit length of the wire(m/L)
Since the second wire is twice as far apart as the first, it will be L2 = 2L1
Let V1 and V2 be the speed of the shorter and longer wire respectively
V1 = √T/M1... 1
V2 = √T/M2... 2
Since V1 = 249m/s, M1 = m/L1 M2 = m/L2 = m/2L1
The equations will now become
249 = √T/(m/L1) ... 3
V2 = √T/(m/2L1)... 4
From 3,
249² = TL1/m...5
From 4,
V2²= 2TL1/m... 6
Dividing equation 5 by 6 we have;
249²/V2² = TL1/m×m/2TL1
{249/V2}² = 1/2
249/V2 = (1/2)²
249/V2 = 1/4
V2 = 249×4
V2 = 996m/s
Therefore the speed of the wave on the longer wire is 996m/s