Answer:
It's constant everywhere in its trajectory.
Explanation:
the projectile was launched with an initial velocity, the only acceleration that is affecting the projectile's velocity is gravity.
The acceleration of gravity is practically equal everywhere on earth, so during its trajectory, we have to take into consideration only the acceleration because of gravity.
This is only correct because the projectile was launched with an initial velocity and it's not accelerating from rest and then falls.
The number of significant digits to the answer of the following problem is four.
<h3>What are the significant digits?</h3>
The number of digits rounded to the approximate integer values are called the significant digits.
The following problem is
(2.49303 g) * (2.59 g) / (7.492 g) =
On solving we get
= 0.86184566204
The answer is approximated to 0.86185
Thus, the significant digits must be four.
Learn more about significant digits.
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A particular atom<span> will have the same number of protons and electrons and most</span>atoms<span> have at least as many neutrons as protons. An </span>element<span> is a substance that is made entirely from one type of </span>atom<span>. For example, the </span>element<span> hydrogen is made from </span>atoms<span> containing just one proton and one electron.
Hope this helps</span>
Answer:
Explanation:
A) <em>Large</em>: As she opens her parachute, she begins to displace a large volume of air. This leads to a Large air resistance
B) <em>increase, weight</em>: As she falls, the air resistance force <u><em>increases</em></u>. Now there is a force acting in opposite directions to her <u><em>weight.</em></u>
C)<em>Weight, Decelerate:</em> The skydiver has only the downward force of her <u><em>weight</em></u> pulling down on her, so she starts to <u><em>decelerate</em></u>
D) <em>Weight, Upward, Resultant</em>:
Her <u><em>weight </em></u>is now equal to the <u><em>upward </em></u>force from the ground. Her <u><em>resultant </em></u>force is then zero
E) <em>Increases, same, constant, resultant, terminal</em>:
As she accelerates faster, the air resistance force <u><em>increases</em></u>. It is now the <u><em>same </em></u>as her weight. She now moves at a <u><em>constant</em></u> speed because the <u><em>resultant </em></u>force acting on her is zero. She is now at her <u><em>terminal </em></u>velocity.
F) <em>Increases, same, constant, terminal</em>:
As she decelerates, the air resistance force on her parachute <u><em>increases </em></u>until it is the <u><em>same</em></u> as her weight. She is now moving with a <u><em>constant </em></u>speed until she hits the ground - a new slower <u><em>terminal</em></u> velocity