If you exert a horizontal force of 200 N to slide a crate across a factory floor at constant velocity, how much friction is exer
ted by the floor on the crate?
1 answer:
Answer:
200 N
Explanation:
Applied force, F = 200 N
Let the friction force is f.
By use of Newton's second law
Net force = mass × acceleration
F - f = m × a
Here acceleration a is zero as crate moves with constant velocity.
So, F - f = 0
f = F
Friction force = 200 N
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