Answer:
Explanation:
The velocity at the inlet and exit of the control volume are same
Calculate the inlet and exit velocity of water jet
The conservation of mass equation of steady flow
since inlet and exit velocity of water jet are equal so the inlet and exit cross section area of the jet is equal
The expression for thickness of the jet
R is the radius
t is the thickness of the jet
D_j is the diameter of the inlet jet
(b)
The negative sign indicate that the direction of the force will be in opposite direction of our assumption
Therefore, the horizontal force is -7603N
Electrostatic force changes like the inverse square of the distance (just like gravity).
If you double the distance, you change the force to 1/4 of what it used to be.
After the move, Objects 1 and 2 attract each other with a force of (18/16) = 1.125 units .
Answer:
C the particle must be somewhere.
Explanation:
This is because normalization of wave function means the maximum probability of finding a particle in a region is 1. And a Wave function describes the probability of finding a particle in region. Also Since it is a probability distribution, its integral over all space must be 1, explaining that the probability that the particle is somewhere and thus it must integrate to 1, meaning it must be it must be normalizable
F = m*a
5000 = 2000 * x
5000/2000 = x
2.5 = x
2.5m/s^2 = a
Answer:
D. power
Explanation:
kg represents mass
(m/v)² represents velocity squared
Then kg·m²/s² represents mass·velocity² = <em>kinetic energy</em> or <em>potential energy</em> or <em>work</em>.
kg·m²/s³ will be the <em>rate of doing work</em>, which is power