I'm not sure if what this question is asking but ill be assuming that the average molecular mass is required. An assuming that the abundance of each isotope is 50% the average molecular mass is 69.82 amu.
1. The formula for
absorbance is given as:
A = log (Io / I)
where A is absorbance, Io
is initial intensity, and I is final light intensity
log (Io / I) = A
log (Io / I) = 2
Io / I = 100
Taking the reverse which is
I / Io:
I / Io = 1 / 100
I / Io = 0.01
Therefore this means that
only 0.01 fraction of light or 1% passes through the sample.
2. What is meant by
transmittance values is actually the value of I / Io. So calculating for A:
at 10% transmittance = 0.10
A = log (Io / I)
A = log (1 / 0.10)
A = 1
at 90% transmittance = 0.90
A = log (Io / I)
A = log (1 / 0.90)
A = 0.046
So the absorbance should be
from 0.046 to 1
3. at 10% transmittance =
0.10
A = log (Io / I)
A = log (1 / 0.10)
<span>A = 1</span>
N(H₂O)=1g÷18g/mol=0,055mol
N(H₂O)=0,055mol · 6·10²³ 1/mol (Avogadro number)= 3,33·10²² molecules.
no, it contains 3 basic particles. (protons, electrons, neutrons)
hope this helped
