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3 years ago

Mg (s) + 2HCl (aq) → MgCl2 (aq) + H2 (g)

Chemistry

2 answers:

Naya [18.7K]3 years ago

8 0

Mg(c) + 237shi (4z) ¥at h2)

valentinak56 [21]3 years ago

7 0

Answer:

Explanation:

So you should obtain 0.1875 moles of H2 The theoretical yield of H2, in grams, can be found by multiplying the 0.1875 moles by the molar mass of H2 (2 grams/mole). We would expect, and love to find, 0.37g in our possession.

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What is the mass of 1.650 mol of aluminum? How many aluminum atoms are in this quantity?

Lostsunrise [7]

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3 years ago

What happens if a acid hits aluminum

satela [25.4K]

Answer:

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3 years ago

Read 2 more answers

Calculate the frequency of the green light emitted by a hydrogen atom with a wavelength of 546 nm.

Alona [7]

Answer: The frequency of the green light emitted by a hydrogen atom with a wavelength of 546 nm is $5.49 \times 10^{14} s^{-1}$ .

Explanation:

Given: Wavelength = 546 nm $(1 nm = 10^{-9} m)$ = $546 \times 10^{-9} m$

The relation between frequency and wavelength is as follows.

$\nu = \frac{c}{\lambda}$

where,

$\nu$ = frequency

c = speed of light = $3.0 \times 10^{8} m/s$

$\lambda$ = wavelength

Substitute the values into above formula as follows.

$\nu = \frac{c}{\lambda}\\= \frac{3.0 \times 10^{8} m/s}{546 \times 10^{-9} m}\\= 5.49 \times 10^{14} s^{-1}$

Thus, we can conclude that the frequency of the green light emitted by a hydrogen atom with a wavelength of 546 nm is $5.49 \times 10^{14} s^{-1}$ .

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3 years ago

You have a 10 gram piece of aluminum and a 10 gram piece of gold sitting in the sun which piece of metal will warm by ten degree

Yuki888 [10]

Answer:

Gold.

Explanation:

Because gold has a lower specific heat than aluminium.

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3 years ago