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3 years ago

PLEASE HELP! I will give brainliest

Chemistry

1 answer:

horsena [70]3 years ago

6 0

Answer:

3.07g of NaCl are present in the solution

Explanation:

A 1.05 M NaCl solution means you have 1.05 moles of NaCl per liter of solution. In 50.0mL = 0.0500L you will have:

0.0500L * (1.05mol / L) = 0.0525 moles of NaCl.

To convert these moles to grams you must use molar mass of the compound (Molar mass NaCl: 58.44g/mol). In 0.0525 moles of NaCl you will have:

0.0525mol * (58.44g / mol) =

<h3>3.07g of NaCl are present in the solution</h3>

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Step 1 : Find moles of crystal violet and NaOH.

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0.018 L + 0.00200 = 0.020 L

Step 3 : Use molarity formula to find final concentrations

Molarity of crystal violet = $\frac{mol(CrystalViolet)}{Total Volume(L) } = \frac{5.4 \times 10^{-5}}{0.020} = 2.7 \times 10^{-3}$

Final concentration of CV = 0.0027 M

Molarity of NaOH= $\frac{mol(NaOH)}{Total Volume(L) } = \frac{5.00 \times 10^{-4}}{0.020} = 0.025 \times 10^{-3}$

NaOH is a strong base and dissociates completely as follows.

$NaOH (aq) \rightarrow Na^{+} (aq) + OH^{-} (aq)$

The mole ratio of NaOH and OH⁻ is 1:1 . Therefore the concentration of OH⁻ is same as that of NaOH.

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