PLEASE HELP! I will give brainliest
1 answer:
Answer:
3.07g of NaCl are present in the solution
Explanation:
A 1.05 M NaCl solution means you have 1.05 moles of NaCl per liter of solution. In 50.0mL = 0.0500L you will have:
0.0500L * (1.05mol / L) = 0.0525 moles of NaCl.
To convert these moles to grams you must use molar mass of the compound (Molar mass NaCl: 58.44g/mol). In 0.0525 moles of NaCl you will have:
0.0525mol * (58.44g / mol) =
<h3>3.07g of NaCl are present in the solution</h3>
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1) Chemical equation
2Al + 6 HCl ---> 2Al Cl3 + 3 H2
2) molar ratios
2 mol Al : 3 moles H2
3) Proportion
2 mol Al / 3mol H2 = x / 9 mol H2
4) Solve for x
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Answer: 6 moles
