Answer:
New substances are produced by a chemical change
Crude oil was formed by hydrocarbons or distillate from decaying animal matter migrating to stratigraphic traps like folds in the sedimentary rocks like anticlines which are dome-shaped folds in the rocks.
In North America, the First Nations used the pitchy tar sands near Fort McMurray to waterproof their canoes long ago before the white man arrived.
In Alberta, the first successful oil well to be drilled was in approximately 1947 called the Leduc well and then oil drilling blossomed from there. Crude oil would be refined to process this oil at that time and broken down into fractions.
Large scale expansion of the oil industry got impetus from the widespread use of automobiles and planes in the early part of the 20th century and then once discoveries like the Leduc well were made, then it became apparent that it was possible to figure out where the oil was and then it blossomed.
In 1907. Leo Baekeland invented bakelite from petroleum ie a polymer.
Nylon and polyester were developed from petroleum in the 1930's and 1941 respectively.,
In 1865, Edward Roberts, an American discovered that by exploding a torpedo with explosive powder in it in an oil well it could increase the well yield by up to 1200%
Peak oil is estimated to be very soon between 2010 and 2030 or most likely before 2020 so anytime soon and after that the reserves are expected to diminish. The world should be converting strongly to alternative energy sources the sooner the better especially to prevent the potential pollution of pipelines and oil tankersl
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Answer:
2C3H8O + 9O2 ==> 6CO2 + 8H2O ... balanced equation
moles propanol = 5.26 g x 1 mol/60.1 g = 0.0875 moles
moles O2 = 31.8 g x 1 mol/31.9 g = 0.997 moles O2
Propanol is limiting based on the mol ratio in balance equation of 2 : 9
To find mass of O2 (excess reagent) left over, we will first find moles O2 used up.
moles O2 used = 0.0875 mol propanol x 9 mol O2/2 mol propanol = 0.394 moles O2 used
moles O2 left over = 0.997 mol - 0.394 mol = 0.603 mol O2 left
mass O2 left = 0.603 mol O2 x 32 g/mol = 19.3 g O2 left over
1.34 L of HF
Explanation:
We have the following chemical reaction:
Sn (s) + 2 HF (g) → SnF₂ (s) + H₂ (g)
First we calculate the number of moles of SnF₂:
number of moles = mass / molecular weight
number of moles of SnF₂ = 5 / 157 = 0.03 moles
From the chemical reaction we see that 1 mole of SnF₂ are produced from 2 moles of SnF₂. This will mean that 0.03 moles of SnF₂ are produced from 0.06 moles of HF.
Now at standard temperature and pressure (STP) we can use the following formula to calculate the volume of HF:
number of moles = volume / 22.4 (L/mole)
volume of HF = number of moles × 22.4
volume of HF = 0.06 × 22.4 = 1.34 L
Learn more about:
problems with gases at STP
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