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Pepsi [2]
3 years ago
11

A plaste horizontally at 150 m/s drops a package from an altitude of 1.3km. How far horizontally the package travel ?

Physics
1 answer:
tatuchka [14]3 years ago
6 0
How ya doing today sir I’m sure not too good cuz u ain’t gettin the answer sry
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The plates of a spherical capacitor have radii 6.25 cm and 15.0 crn. The space between the two spheres is filled with a material
aleksklad [387]

Answer:

Capacitance is 0.572×10⁻¹⁰ Farad

Explanation:

Radius = R₁ = 6.25 cm = 6.25×10⁻² m

Radius = R₂ = 15 cm = 15×10⁻² m

Dielectric constant = k = 4.8

Electric constant = ε₀ = 8.854×10⁻¹² F/m

ε/ε₀=k

ε=kε₀

Capacitance\ (C)=\frac{4\pi k\epsilon_0 R_1\times R_2}{R_2-R_1}\\\Rightarrow C=\frac{4\pi 4.8\times 8.854\times 10^{-12}\times 15\times 10^{-2}\times 6.25\times 10^{-2}}{15\times 10^{-2}-6.25\times 10^{-2}}\\\Rightarrow C=0.572\times 10^{-10}\ Farad

∴ Capacitance is 0.572×10⁻¹⁰ Farad

3 0
3 years ago
A hiker walks 11 km due north from camp and then turns and walks 11 km due east. What is the magnitude of the displacement (on a
sattari [20]

Answer:

16 km

Explanation:

Drawing a right triangle to model the problem helps. I started by drawing the lines of the triangle to model the hiker's journey- a vertical straight line for 11 km north and then a horizontal line connected to the top of it for 11 km east; I then drew the hypothenuse to connect the two lines.

The hypothenuse is what we have to solve for, so we will use the Pythagorean Theorem, a^2 + b^2 = c^2. Since both distances are 11 km both a and b in the equation are 11.

11^2 + 11^2 = c^2

121 + 121 = c^2

242 = c^2

c = 15.56

Rounding the answer makes it 16 km for the hiker's magnitude of displacement.

5 0
4 years ago
A combustion reaction usually gives off heat and light is it true or false
yanalaym [24]
The answer is true I think
3 0
4 years ago
At what time were the racers at the same position?<br> O 15<br> O 3s<br> O 5s<br> 0 4s
Jlenok [28]
The Answer is:

O 3s

Hope you got it right.
5 0
3 years ago
Read 2 more answers
A boat moves initially at 10 m/s, then accelerates at 2 m/s^2 for 10 s. What is the velocity of the boat after 10 s?
bija089 [108]

Answer:

<h3>30m/s</h3>

Explanation:

acceleration is the change in velocity of a body with respect to time

a = v-u/t

v is the final velocity

u is the initial velocity = 10m/s

t is the time taken = 10s

a is the acceleration = 2m/s²

substitute the values into the formula

2 = v-10/10

cross multiply

20 = v-10

v = 20+10

v = 30m/s

Hence the velocity of the body after 10s is 30m/s

6 0
4 years ago
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