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Makovka662 [10]
3 years ago
9

If a Is close enough to a ,then it will form a nova?

Physics
1 answer:
BARSIC [14]3 years ago
4 0
Wat... are you even asking..
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In a sea community near the floor of the ocean, a great white shark summons a goby fish to attach itself under its stomach. The
lubasha [3.4K]

Answer:

Commensalism

Explanation:

Commensalism is one example of the behavior of a goby and shark.

3 0
3 years ago
Read 2 more answers
Calculate the ionization potential for C+5 ( 5 electrons removed for the C atom) and in addition compute the wavelength of the t
sveta [45]

Answer:

Ionization potential of C⁺⁵ is 489.6 eV.

Wavelength of the transition from n=3 to n=2 is 1.83 x 10⁻⁸ m.

Explanation:

The ionization potential of hydrogen like atoms is given by the relation :

E = \frac{13.6Z^{2} }{n^{2} } eV     .....(1)

Here <em>E</em> is ionization potential, <em>Z</em> is atomic number and <em>n</em> is the principal quantum number which represents the state of the atom.

In this problem, the ionization potential of Carbon atom is to determine.

So, substitute 6 for <em>Z</em> and 1 for <em>n</em> in the equation (1).

E = \frac{13.6\times(6)^{2} }{1^{2} }

<em> E = </em>489.6 eV

The wavelength (λ)  of the photon due to the transition of electrons in Hydrogen like atom is given by the relation :

\frac{1}{\lambda} =RZ^{2}[\frac{1}{n_{1} ^{2}}-\frac{1}{n_{2} ^{2} }]     ......(2)

R is Rydberg constant, n₁ and n₂ are the transition states of the atom.

Substitute 6 for Z, 2 for n₁, 3 for n₂ and 1.09 x 10⁷ m⁻¹ for R in equation (2).

\frac{1}{\lambda} =1.09\times10^{7} \times6^{2}[\frac{1}{2 ^{2}}-\frac{1}{3 ^{2} }]

\frac{1}{\lambda}  = 5.45 x 10⁷

λ = 1.83 x 10⁻⁸ m

7 0
4 years ago
The gravitational force between two objects with masses, m1 and m2, separated by a distance "r" is given by F = (Gm1m2)/ r2, whe
diamong [38]

Answer:

it increases

Explanation:

4 0
3 years ago
Seeds are often found on which part of a gymnosperm?<br><br> branch<br> leaf<br> cone<br> stem
inn [45]
Cone i hope this helps
8 0
3 years ago
student built a simple heat engine that could lift masses. If the heat engine takes in 300 J of heat and loses 50 J to the envir
k0ka [10]

Answer:

So it will lift the mass by h = 17 m

Explanation:

As per energy conservation we know that

Q_1 = W + Q_2

here we know that

Q_1 = 300 J

Q_2 = 50 J

now we have

W = 300 - 50

W = 250 J

so work done by the engine is 250 J

now we have

W = mgh

250 = 1.5 \times 9.81 \times h

h = 17 m

4 0
3 years ago
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