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3 years ago

Hydrogen and chlorine react to form hydrogen chloride, like this:

Chemistry

1 answer:

REY [17]3 years ago

3 0

Answer:

the value of the equilibrium constant Kp for this reaction is 0.275

Explanation:

Step 1: Data given

Pressure HCl at the equilibrium = 18.0 atm

Pressure H2 at the equilibrium = 25.4 atm

Pressure Cl2 at the equilibrium = 46.4 atm

Step 2: The balanced equation

H2(g) + Cl2(g) → 2 HCl(g)

Step 3: Calculate the value of the equilibrium constant Kp for this reaction

Kp = (pHCl)² / (pH2*pCl2)

Kp = 18.0² / (25.4 * 46.4)

Kp = 324 / 1178.56

Kp = 0.275

the value of the equilibrium constant Kp for this reaction is 0.275

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Rewrite this measurement with a simpler unit, if possible. <br> 8.3 kg•m^2/ s^2

Feliz [49]

Answer: 8.3 J

Explanation:

We have the following measurement:

$8.3 \frac{kg m^{2}}{s^{2}}$

Rearranging the units:

$8.3 \frac{kg m}{s^{2}}m$

Since 1 Newton is $1 N=1 \frac{kg m}{s^{2}}$ :

$8.3 Nm$

Since 1 Joule is $1 J=1 Nm$ :

$8.3 J$ This is the simplest form possible

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2 years ago

The ksp of calcium carbonate, caco3, is 3.36 × 10-9 m2. calculate the solubility of this compound in g/l.

maw [93]

CaCO₃ partially dissociates in water as Ca²⁺ and CO₃²⁻. The balanced equation is,
CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻(aq)
Initial Y - -
Change -X +X +X
Equilibrium Y-X X X

Ksp for the CaCO₃(s) is 3.36 x 10⁻⁹ M²

Ksp = [Ca²⁺(aq)][CO₃²⁻(aq)]
3.36 x 10⁻⁹ M² = X * X
3.36 x 10⁻⁹ M² = X²
X = 5.79 x 10⁻⁵ M

Hence the solubility of CaCO₃(s) = 5.79 x 10⁻⁵ M
= 5.79 x 10⁻⁵ mol/L

Molar mass of CaCO₃ = 100 g mol⁻¹

Hence the solubility of CaCO₃ = 5.79 x 10⁻⁵ mol/L x 100 g mol⁻¹
= 5.79 x 10⁻³ g/L

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3 years ago

What is the main type of weathering in deserts? weathering by organic acids chemical weathering physical weathering

Solnce55 [7]

Answer:

chemical

Explanation:

Chemical weathering, which is the decomposition of a rock by the alteration of its chemical composition.

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3 years ago

5. In order for a bowling ball to move down the lane and strike pins, what must be applied to the ball?

Marizza181 [45]

Answer:

c i think

Explanation:

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2 years ago

Read 2 more answers

How many moles are in 5.6x1025 molecules of calcium oxide?

Vlad1618 [11]

Answer:

<h2>93.02 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{5.6 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 93.023...$

We have the final answer as

<h3>93.02 moles</h3>

Hope this helps you

8 0

2 years ago