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3 years ago

What is a wave period?

Physics

1 answer:

Kamila [148]3 years ago

8 0

A wave period is the time it takes to complete one cycle

I hope that's help:0

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Anyone know the answer ?

dlinn [17]

Momentum = mass x velocity, so 500kg x 2m/s = 1000 kg m/s

5 0

3 years ago

Read 2 more answers

Calculate the kinetic energy in joules of a 1200 kg automobile moving at 18 m/s .

vodka [1.7K]

Answer:

194,400 joules of kinetic energy.

Explanation:

Remember that to calculate the Kinetic energy you need to use the next formula:

$Ke=\frac{1}{2}Mass*Velocity^2$

We know that Mass= 1200 kg and velocity is 18m/s, so we insert those values into the formula:

$Ke=\frac{1}{2}Mass*Velocity^2\\Ke=\frac{1}{2}1200kg*(18m/s)^2\\Ke=194,400 joules$

So the kinetic energy of a car moving at 18m/s with a mass of 1200 kg would be 194,400 joules.

7 0

3 years ago

Read 2 more answers

The power in an electric circuit varies inversely with the resistance. If the power is 2,200 watts when the resistance is 25 ohm

valentinak56 [21]

Answer:

The value of resistance when power is 1100 watts = $R_{2}$ = 50 ohms

Explanation:

Power $P_{1}$ = 2200 Watts

Resistance $R_{1}$ = 25 ohms

Power $P_{2}$ = 1100 Watts

Resistance $R_{2}$ = we have to calculate

Given that the power in an electric circuit varies inversely with the resistance

⇒ P ∝ $\frac{1}{R}$

⇒ $\frac{P_{2} }{P_{1} }$ = $\frac{R_{1} }{R_{2} }$

⇒ $\frac{1100}{2200}$ = $\frac{25}{R_{2} }$

⇒ $R_{2}$ = 50 ohms

This is the value of resistance when power is 1100 watts.

6 0

4 years ago

Due to the earth's rotation, a person would be traveling faster at the equator than they would at a position halfway from the eq

Kisachek [45]

Answer:

False

Explanation:

It is actually the exact opposite.

8 0

3 years ago

Read 2 more answers

4. What's the voltage drop if V, = 56 V, V2 = 35 V, and V3 = 3 V

Murrr4er [49]

Answer:

The correct option is A. 18 V

Therefore,

$V_{1}=18\ V$

Explanation:

Given:

Total Voltage,

V = 56 V,

Voltage drop

$V_{2}=35\ V$

$V_{3}=3\ V$

To Find:

$V_{1}=?$ (Assumed ,as it is not given clearly in the question)

Solution:

So in series combination total Voltage is given as

$V=V_{1}+V_{2}+V_{3}$

Substituting the values we get

$56=V_{1}+35+3\\\\V_{1}=56-38=18\ V$

Therefore,

$V_{1}=18\ V$

5 0

3 years ago