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Answer:- 335 kcal of heat energy is produced.
Solution:- The balanced equation for the combustion of glucose in presence of oxygen to give carbon dioxide and water is:
From given info, 2803 kJ of heat is released bu the combustion of 1 mol of glucose. We need to calculate the energy produced when 3.00 moles of oxygen react with excess of glucose.
We could solve this using dimensional analysis as:
= 1401.5 kJ
Now, let's convert kJ to kcal.
We know that, 1kcal = 4.184kJ
So,
= 335 kcal
Hence, 335 kcal of heat energy is produced by the use of 3.00 moles of oxygen gas.
Answer:
The right answer is "8.81 atm".
Explanation:
Given:
V = 5.00 L
Mass = 4900 g
MW = 32 g/mol
T = 350 K
Now,
Number of moles will be:
By using the ideal gas equation, we get
⇒
or,
⇒
By substituting the values, we get