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3 years ago

WHAT IS KNOWN AS HYBRIDIZATION

Chemistry

2 answers:

gayaneshka [121]3 years ago

4 0

$\red{ \bold {\huge{ \textit{ \boxed {{\blue{QUESTION}}}}}}}$

WHAT IS KNOWN AS HYBRIDIZATION

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$\orange{\underline{\huge{\bold{\textit{\green{\bf{HYBRIDIZATION}}}}}}}$

<h3> It is the change in the orbitals of the central atom of the molecule to form bonds with other atom if same type or another type.</h3>

The hybrid orbitals r of same level .

The Hybridization takes place in between orbitals of equal or very less energy levels to form same level of energy in all orbitals.

The orbitals combine is always equal to The number of orbitals formed

The names of hybridized orbitals r kept according to the orbital which r combined to form them

sp orbital :- one s and one p combine to form sp orbital

$s {p}^{2}$ orbital :- one s and two p orbitals combine to form it..

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topjm [15]3 years ago

4 0

Answer:

mark me brain list

Explanation:

answer kr dia app ne kiha tha

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How many moles are in 187.54 grams of magnesium chlorate?

Svetlanka [38]

Hey there!

Magnesium chlorate: Mg(ClO₃)₂

Find molar mass.

Mg: 1 x 24.305 = 24.305

Cl: 2 x 35.453 = 70.906

O: 6 x 16 = 96

------------------------------------

191.211 g/mol

We have 187.54 grams.

187.54 ÷ 191.211 = 0.9808

There are 0.9808 moles in 187.54 grams of magnesium chlorate.

Hope this helps!

3 0

3 years ago

Complete this sentence. If mass remains the same while the volume of a substance ________, the density of the substance will____

VARVARA [1.3K]

Answer:

B. Increases, Decreases

Explanation:

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4 0

3 years ago

A student heats 10.52 g of sodium hydrogen carbonate in a crucible until the compound completely decomposes to sodium carbonate

saveliy_v [14]

Answer:

$m_{Na_2CO_3}^{theoretical}=6.636gNa_2CO_3$

Explanation:

Hello!

In this case, since the decomposition of sodium hydrogen carbonate is:

$2NaHCO_3(s)\rightarrow Na_2CO_3(s)+H_2O(g)+CO_2(g)$

Thus, since there is a 2:1 mole ratio between the sodium hydrogen carbonate and sodium carbonate, and the molar masses are 84.01 and 105.99 g/mol respectively, we obtain the following theoretical yield:

$m_{Na_2CO_3}^{theoretical}=10.52gNaHCO_3*\frac{1molNaHCO_3}{84.01gNaHCO_3}*\frac{1molNa_2CO_3}{2molNaHCO_3} *\frac{105.99gNa_2CO_3}{1molNa_2CO_3}\\\\ m_{Na_2CO_3}^{theoretical}=6.636gNa_2CO_3$

Best regards!

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3 years ago

Express the following quantity in scientific notation. The answer needs to have the correct number of significant figures. 21,30

melisa1 [442]

2.13 x 10 E 7 i believe this is correct

4 0

4 years ago

Read 2 more answers

A chemistry graduate student is given of a chlorous acid solution. Chlorous acid is a weak acid with . What mass of should the s

DerKrebs [107]

Answer:

11.31g NaClO₂

Explanation:

<em> Is given 250mL of a 1.60M chlorous acid HClO2 solution. Ka is 1.110x10⁻². What mass of NaClO₂ should the student dissolve in the HClO2 solution to turn it into a buffer with pH =1.45? </em>

It is possible to answer this question using Henderson-Hasselbalch equation:

pH = pKa + log₁₀ [A⁻] / [HA]

<em>Where pKa is -log Ka = 1.9547; [A⁻] is the concentration of the conjugate base (NaClO₂), [HA] the concentration of the weak acid</em>

You can change the concentration of the substance if you write the moles of the substances:

[Moles HClO₂] = 250mL = 0.25L×(1.60mol /L) = <em>0.40 moles HClO₂</em>

Replacing in H-H expression, as the pH you want is 1.45:

1.45 = 1.9547 + log₁₀ [Moles NaClO₂] / [0.40 moles HClO₂]

-0.5047 = log₁₀ [Moles NaClO₂] / [0.40 moles HClO₂]

<em>0.3128 = </em>[Moles NaClO₂] / [0.40 moles HClO₂]

0.1251 = Moles NaClO₂

As molar mass of NaClO₂ is 90.44g/mol, mass of 0.1251 moles of NaClO₂ is:

0.1251 moles NaClO₂ ₓ (90.44g / mol) =

<h3>11.31g NaClO₂</h3>

5 0

3 years ago

WHAT IS KNOWN AS HYBRIDIZATION​

WHAT IS KNOWN AS HYBRIDIZATION