Question

What are the values of the coefficients and constant term of 0 = 4 – 7x2 + x in standard form?

Answer 1

Answer

a = -7 × 10⁰

b = 1 × 10⁰

c = 4 × 10⁰

Explanation

The general formula is; ax² + bx + c.

Where a ⇒ co-efficient of x²

           b ⇒ co-efficient of x

           c ⇒ The constant term

0 = 4 – 7x² + x This equation can be written in the form of  ax² + bx + c.

0 = 4 – 7x² + x = -7x² + x + 4 = 0

Comparing the values of a, b and c in the equation in standard form are;

a = -7 × 10⁰

b = 1 × 10⁰ and

c = 4 × 10⁰

Answer 2

By definition, the standard parabola equation is given by:
 $ax ^ 2 + bx + c = 0$
 We then have the following quadratic equation:
 $0 = 4 - 7x ^ 2 + x$
 By rewriting the equation in its standard form, we have:
 $- 7x ^ 2 + x + 4 = 0$
 Comparing with the definition, we have that the values of the coefficients are given by:
 $a = -7 b = 1 c = 4$
 Answer:
 The values of a, b and c are given by:
 $a = -7 b = 1 c = 4$