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stepan [7]
3 years ago
11

How many moles are in 135g of Teflon?

Chemistry
1 answer:
Oliga [24]3 years ago
5 0

1.34 moles are in 135g of Teflon.

Explanation:

Molecular formula of teflon is (C2H4)n

mass of teflon = 135 grams

atomic mass of teflon = 100.01 gram/mole

number of moles of teflon = ?

Formula used to calculate number of moles in a substance is given as:

number of moles = \frac{mass}{atomic mass of 1 mole}

putting the values in the above equation:

number of moles = \frac{135}{100.01}

number of moles = 1.34 moles

Teflon is polymer which is used for making non-stick coating, in 135 grams of teflon there are 1.34 moles in it.

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What would be the composition and ph of an ideal buffer prepared from lactic acid (ch3chohco2h), where the hydrogen atom highlig
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Answer:

P_H =2.86

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Explanation:

first write the equilibrium equaion ,

C_3H_6O_3  ⇄ C_3H_5O_3^{-}  +H^{+}

assuming degree of dissociation \alpha =1/10;

and initial concentraion of C_3H_6O_3 =c;

At equlibrium ;

concentration of C_3H_6O_3 = c-c\alpha

[C_3H_5O_3^{-}  ]= c\alpha

[H^{+}] = c\alpha

K_a = \frac{c\alpha \times c\alpha}{c-c\alpha}

\alpha is very small so 1-\alpha can be neglected

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K_a = {c\alpha \times \alpha}

[H^{+}] = c\alpha = \frac{K_a}{\alpha}

P_H =- log[H^{+} ]

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K_a =1.38\times10^{-4}

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composiion ;

c=\frac{1}{\alpha} \times [H^{+}]

[H^{+}] =antilog(-P_H)

[H^{+} ] =0.0014

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