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Ivan
2 years ago
13

2) A solution consists of 0.50 mole of CaCl2 dissolved i

Chemistry
2 answers:
raketka [301]2 years ago
8 0
Your answer would be (A) a higher boiling point and a lower freezing point
Aleksandr-060686 [28]2 years ago
6 0

A. a higher boiling point and a lower freezing point

Explanation:

hope this helps :)

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(part 1 of 3) Copper reacts with silver nitrate through a single replacement. If 1.29 g of silver are produced from the reaction
ale4655 [162]

Answer:

See explanation.

Explanation:

Hello there!

In this case, according to the described chemical reaction, we first write the corresponding equation to obtain:

Cu+2AgNO_3\rightarrow 2Ag+Cu(NO_3)_2

Thus, we proceed as follows:

Part 1 of 3: here, since the molar mass of silver and copper (II) nitrate are 107.87 and 187.55 g/mol respectively, and the mole ratio of the former to the latter is 2:1, we can set up the following stoichiometric expression:

m_{Cu(NO_3)_2}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu(NO_3)_2}{2molAg}*\frac{187.55gCu(NO_3)_2}{1molCu(NO_3)_2}   \\\\m_{Cu(NO_3)_2}=1.12gCu(NO_3)_2

Part 2 of 3: here, the molar mass of copper is 63.55 g/mol and the mole ratio of silver to copper is 2:1, the mass of the former that was used to start the reaction was:

m_{Cu}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu}{2molAg}*\frac{63.55gCu)_2}{1molCu}   \\\\m_{Cu}=0.380gCu

Part 3 of 3: here, the molar mass of silver nitrate is 169.87 g/mol and their mole ratio 2:2, thus, the mass of initial silver nitrate is:

m_{AgNO_3}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{2molAgNO_3}{2molAg}*\frac{169.87gAgNO_3}{1molAgNO_3}   \\\\m_{AgNO_3}=2.03gAgNO_3

Best regards!

5 0
3 years ago
Please help ASAP! I’m lost right now.
SCORPION-xisa [38]
1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^5, 4s^1

Chromium is strange because it moves on to the 4s orbital instead of filling the 3d orbital with that last electron. Tricky.

Mark as brainliest if this helped! :)
3 0
3 years ago
NEED HELP ASAP!!!!!!!!!!!!!!!!!!!!!!
Paraphin [41]
<h2>Answer:  C) 1s²2s²2p⁶</h2>

<h3>Explanation:</h3>

A noble gas has 8 electrons between the p and s orbitals of the outer shell. Helium is the exception because it only has two electrons.

<h3>                       ∴  1s²2s²2p⁶ is the noble gas (neon)</h3>

7 0
2 years ago
Please help me I will give you the brain thing and extra points. image below part
jekas [21]
D is the correct answer... if u need in depth let me know
3 0
3 years ago
Read 2 more answers
Suppose that on a dry, sunny day when the air temperature is near 37 ∘C,37 ∘C, a certain swimming pool would increase in tempera
ioda

Answer:

The fraction of water body necessary to keep the temperature constant is 0,0051.

Explanation:

Heat:

Q=m*Ce*ΔT

Q= heat  (unknown)

m= mass  (unknown)

Ce= especific heat (1 cal/g*°C)

ΔT= variation of temperature  (2.75 °C)  

Latent heat:

ΔE=∝mΔHvap

ΔE= latent heat

m= mass  (unknown)

∝= mass fraction (unknown)

ΔHvap= enthalpy of vaporization (539.4 cal/g)

Since Q and E are equal, we can match both equations:

m*Ce*ΔT=∝*m*ΔHvap

Mass fraction is:

∝=\frac{Ce*ΔT}{ΔHvap}

∝=\frac{(1 cal/g*°C)*2.75°C}{539.4 cal/g}

∝=0,0051

7 0
3 years ago
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