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Nina [5.8K]
3 years ago
6

What is the maximum range of most handheld fire extinguishers?        A. 50 yd   B. 30 ft   C. 10 ft   D. 100 ft

Physics
2 answers:
alex41 [277]3 years ago
5 0
C- 10ft. Hope this helped. Have a great day! :D
olchik [2.2K]3 years ago
5 0
Hello,


I believe that they answer is 10 feet. 30 feet would be to much. 10 feet is enough because so that you wont be to close to the fire


Hope this help, and btw,the answer is C
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A capacitor is made from two hollow, coaxial, iron cylinders, one inside the other. The inner cylinder is negatively charged and
kari74 [83]

Answer:

a. 4.2057\times 10^-^1^2 F \ or 4.2057\ pF\\b. 2.7344V

Explanation:

a.

Given the permittivity constant to be 8.854\times 10^-^1^2 F/m,The capacitance of a cylindrical \ capacitor of length, L is given by the equation:

C=\frac{2\pi \epsilon _o L}{ln(b/a)} where b is the radius of the outer cylinder and a the radius of the inner cylinder.

The values are given as:a=0.550mm(5.5\times 10^-^4m), \ b=4.00mm(4.0\times10^-^3m), \ L=15.0cm(0.150m)

Substitute in our capacitance equation:

C=\frac{2\times\pi \times 8.854\times 10^-^1^2 \times 0.15}{In(4.00/0.550)}\\=4.2057\times 10^-^1^2 F

Hence the capacitance is 4.2057\times 10^-^1^2 F

b. The charge on the capacitance is related to the potential difference across it. The potential difference is expressed using the equation:

Q=CV,Q=11.5pC

From a above, we already have our capacitance value,C=4.2057\times 10^-^1^2 F

We substitute C in the pd equation:

v=>(11.5)/(4.2057)\\=2.7344V

Hence, the applied potential difference is 2.7344V

4 0
3 years ago
Why is most space exploration accomplished with spacecraft that do not have astronauts on board
Olin [163]
Because of the enormous expense of creating conditions aboard
a spacecraft in which astronauts can survive, and the huge extra
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6 0
3 years ago
Read 2 more answers
Given that the distance from the left end of the string to the first antinode is 27.5 cm , calculate the wavelength of the stand
ivolga24 [154]

Answer:

= 0.55 m

Explanation:

A standing wave is characterized by anti-nodes and nodes.

Antinodes are points on a standing wave at maximum amplitude, while nodes are points on the standing wave that are stationary and have zero amplitude.

The distance between two adjacent nodes or two adjacent anti-nodes is equivalent to half the wavelength.

Therefore, in this case the half wavelength is 27.5 cm.

Thus, wavelength = 27.5 × 2

                              = 55 cm

                             <u>= 0.55 m</u>

6 0
2 years ago
Write a short description of how the motion of the racers might change from the start of the race to the finish line
Ad libitum [116K]
The motion of the racers might change from the start because the pressure goes up so all the racer wants is to speed up and win, so when the racer first starts he or she is calm because he's not driving yet and when he or she is on his/hers way to he finish line he/she just wants to win and gets under pressure so he speeds up even more and drifts. Your welcome
6 0
3 years ago
A baseball is hit at ground level. The ball reaches its maximum height above ground level 3.0 s after being hit. Then 2.5 s afte
vaieri [72.5K]

Answer:

Part a)

H = 44.1 m

Part b)

y = 13.48 m

Part c)

d = 8.86 m

Explanation:

Part a)

As we know that ball will reach at maximum height at

t = 3 s

now we will have

t = \frac{v sin\theta}{g}

now we have

3 = \frac{vsin\theta}{9.8}

v sin\theta = 29.4 m/s

Now maximum height above ground is given as

H = \frac{v^2sin^2\theta}{2g}

H = \frac{29.4^2}{2(9.8)}

H = 44.1 m

Part b)

Height of the fence is given as

y = (vsin\theta) t - \frac{1}{2}gt^2

y = (29.4)(5.5) - \frac{1}{2}(9.8)(5.5^2)

y = 13.48 m

Part c)

As we know that its horizontal distance moved by the ball in 5.5 s is given as

x = v_x t

97.5 = v_x (5.5)

v_x = 17.72 m/s

now total time of flight is given as

T = 3 + 3 = 6 s

so range is given as

R = v_x T

R = (17.72)(6)

R = 106.4 m

so the distance from the fence is given as

d = 106.4 - 97.5

d = 8.86 m

7 0
3 years ago
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