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Nina [5.8K]
3 years ago
6

What is the maximum range of most handheld fire extinguishers?        A. 50 yd   B. 30 ft   C. 10 ft   D. 100 ft

Physics
2 answers:
alex41 [277]3 years ago
5 0
C- 10ft. Hope this helped. Have a great day! :D
olchik [2.2K]3 years ago
5 0
Hello,


I believe that they answer is 10 feet. 30 feet would be to much. 10 feet is enough because so that you wont be to close to the fire


Hope this help, and btw,the answer is C
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In a nuclear fusion reaction two 2H atoms are combined to produce one 4He.
Mrrafil [7]

Answer:

a)= 0.025602u

b) = 23.848MeV

c) N = 1.546 × 10¹³

Explanation:

The reaction is

²₁H   +   ²₁H   ⇄   ⁴₂H + Q

a) The mass difference is

Δm = 2m(²₁H) - m (⁴₂H)

       = 2(2.014102u) - 4.002602u

        = 0.025602u

b) Use the Einstein mass energy relation ship

The enegy  release is the mass difference times 931.5MeV/U

E = (0.025602) (931.5)

   = 23.848MeV

c)

the number of reaction need per seconds is

N = Q/E

     = 59W/ 23.848MeV

  = \frac{59}{(23.848 \times 10^6 )(1.6 \times 10^1^9) } \\\\= 1.546 \times 10^1^3

N = 1.546 × 10¹³

5 0
3 years ago
Why is it important to use democratic method of choosing someone for a position of authority
dangina [55]
So that the correct representative of the people gets elected to head the people- so that a person who is thought to be capable enough to rule over people and take the correct decisions may be representative to the people.
4 0
3 years ago
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A car is going south on I-69 at 33 m/s (74 mph). The car has good brakes so its maximum braking acceleration is – 8.5 m/s^2 . Tr
dmitriy555 [2]

Answer:

1.69515 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-33^2}{2\times -8.5}\\\Rightarrow s=64.06\ m

The distance between the traffic and the car after braking is 120-64.06 = 55.94 m

Time = Distance / Speed

\text{Time}=\frac{55.94}{33}\\\Rightarrow \text{Time}=1.69515\ seconds

The reaction time cannot be more than 1.69515 seconds

4 0
3 years ago
what will the stopping distance be a a 3000-kg car if -3000N of force are applied when the car is traveling 10 m/s
Inga [223]

Answer:

50 m

Explanation:

Acceleration= force/mass

3000/3000=1m/s^-2

Applying equation of motion:

V^2=U^2+2as; V is final velocity, u is initial velocity, a is acceleration and s is the distance covered.

0=10^2 -2*1s;

Solve for s

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3 years ago
The magnetic field 0.02 m from a wire is 0.1 t. what is the magnitude of the magnetic field 0.01 m from the same wire?
juin [17]

Answer:

0.2 T

Explanation:

3 0
3 years ago
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