Given: Mass m = 44 Kg; Velocity v = 10 m/s
Required: Kinetic energy K.E = ?
Formula: K.E = 1/2 mv²
K.E 1/2 (44 Kg)(10 m/s)²
K.E = 2,200 Kg.m²/s²
K.E = 2,200 J Answer is A
Answer: When a liquid or gas is heated, the molecules move faster, bump into each other, and spread apart. Because the molecules are spread apart, they take up more space. ... The molecules move more slowly and take up less space. Therefore temperature can affect density.
Explanation:
Answer: D
Explanation: Because the orginal Penalty stroke is Today's field hockey topic is the exciting penalty stroke! What is a stroke? A penalty stroke occurs when an intentional foul happens in the penalty circle (the circle around the goal), the foul prevents a scoring of a opportunity.
Answer:
See Explanation Below
Explanation:
This question is incomplete.
I'll answer this question on general terms. You'll get your result if you apply the steps I'll highlight below.
To start with; what's Ampere law;
It states that for any closed loop path, the sum of the length elements times the magnetic field in the direction of the length element is equal to the permeability times the electric current enclosed in the loop.
The simple translation of this law is that, the sum of current in the close loop gives us the desired result.
Rephrasing your question;
Three currents, (I1 = +3A, I2 = +4A and I3 = -5A) are passing through a surface bounded by a closed path. The currents have different values and directions. According to Ampere’s law, what is the value of I on the right side of this equation?
First, we take note of the signs in front of the given currents.
The negative sign in front of I3 means that; it is moving in opposite direction of I1 and I2.
To calculate the value of I.
The value of I is the sum of the three currents:
i.e. 3A + 4A - 5A
I = 2 A
Explanation:
Given that,
Fapp = 67.0 N at 30.0° above the horizontal (rightward and upward)
Fnorm = 64.5 N, up
Ffrict = 27.6 N, left
Fgrav = 98 N, down
(a) Resolution of the applied force:
Horizontal component,
Vertical component,
(b) Net horizontal force :
It is positive, it will act in right side
Net vertical force :
Hence, it is clear that the net force is in horizontal direction i.e. 30.42 N due right side.
