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Stels [109]
2 years ago
9

Whitch two options are forms of kinetic energy?

Physics
1 answer:
valentina_108 [34]2 years ago
7 0

Answer:the witch has nothing to do with the problem

Explanation:

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Does the collision between the cart and the brick follow the law of momentum conservation? Make a claim (yes or no) and support
murzikaleks [220]

Answer:

yes it does

Explanation:

Going by the law of conservation of momentum, when two objects collides, the momentum of one object is transferred to the other object.

This collision can be elastic or inelastic coliision

let the mass of the brick be m1

the mass of the cart be m2

the velocity (initial and final) of the brick  u1 and v1

the velocity (initial and final) of the cart u2 and v2

For elastic collision

m1u1+m2u2= m1v1+m2v2

For inelastic collision the two bodies will move with the same velocity after impact

m1u1+m2u2=(m1+m2)V

7 0
3 years ago
HELP I'll MARK BRAINLY
AURORKA [14]

Answer:

it is plate tectonics option D hope it helps

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8 0
2 years ago
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Can someone help me on 2 science question,
gavmur [86]
1. I think you should compare diagrams of moon phases from the textbook to diagrams of moon phases online. Because if you pick D it will take to long and C will help you out whith 3 different things to look at. 

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8 0
3 years ago
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A solid cylinder with a mass of 2.72 kg and a radius of 0.083 m starts from rest at a height of 4.20 m and rolls down a 88.7 ◦ s
Bingel [31]

Explanation:

According to the law of conservation of energy ,    

             Potential energy = kinetic energy

   mgh = \frac{1}{2} \times mv^{2} + \frac{1}{2} \times I \times \omega^{2}

                  I = \frac{mr^{2}}{2}

          \omega = \frac{v}{r}

     mgh = [\frac{1}{2} \times mv^{2}] + [\frac{1}{2} \times (\frac{mr^{2}}{2}) \frac{v^{2}}{r^{2}}]

     mgh = [\frac{1}{2} \times mv^{2}] + [\frac{1}{4} \times mv^{2}]

             g \times h = \frac{3}{4} \times v^{2}

             9.8 \times 4.2 = \frac{3}{4} \times v^{2}

                  v = 7.4 m/s

thus, we can conclude that the translational speed of the cylinder when it leaves the incline is 7.4 m/s.

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3 years ago
When a 12 newton horizontal force is applied to a box on a horizontal
sdas [7]

Answer:

ur mum

Explanation:

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