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schepotkina [342]
3 years ago
8

What are scientific models used for? Give an example of each of the following types of models: Idea, Physical, Compute

Chemistry
1 answer:
7nadin3 [17]3 years ago
7 0

Answer:

Scientific models are used to explain and predict the behaviour of real objects or systems and are used in a variety of scientific disciplines, ranging from physics and chemistry to ecology and the Earth sciences.

Explanation:

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How many moles are in 4.24kg of Na2CO3?
frosja888 [35]
40.0 is the answer, sorry, I had some lag, I would've answered it like 5 minutes ago

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8 0
3 years ago
Can someone help me with this
Trava [24]

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2 years ago
Be sure to answer all parts. Write a balanced equation (including physical states) for the following reaction: Sodium carbonate,
aalyn [17]

Answer:

I think it would be:

NaCO3 (s)-->Na2O (s) + CO2 (g)

3 0
3 years ago
What mass, in grams, of CO2 and H20 N<br> is formed from 2.55 mol of propane?
Black_prince [1.1K]

Answer: The mass of CO_2 and H_2O produced are 336.6 g and 183.6 g respectively.

Explanation:

The combustion reaction between propane and oxygen leads to formation of carbon dioxide and water.

Law of Conservation of mass states that the mass will remain constant for a balanced equation. This is carried out when the total number of atoms on reactant side is same as the total number of atoms on the product side. Thus the equation must be balanced.

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

a) 1 mol of propane produces = 3 moles of CO_2

Thus 2.55 mol of propane produces = \frac{3}{1}\times 2.55=7.65 moles of [tex]CO_2

mass of CO_2=moles\times {\text {molar mass}}=7.65mol\times 44g/mol=336.6g

b) 1 mol of propane produces = 4 moles of H_2O

Thus 2.55 mol of propane produces = \frac{4}{1}\times 2.55=10.2 moles of [tex]H_2O

mass of H_2O=moles\times {\text {molar mass}}=10.2mol\times 18g/mol=183.6g

The mass of CO_2 and H_2O produced are 336.6 g and 183.6 g respectively.

8 0
2 years ago
HELP ME PLEASE!!!!!!!!
Licemer1 [7]

The correct answer is “Radiation.”

8 0
2 years ago
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