The balanced reaction for combustion is as follows ;
2C₂H₅OH + 6O₂ ---> 4CO₂ + 6H₂O
the stoichiometry of C₂H₅OH to O₂ is 2:6
that means 2 mol of C₂H₅OH reacts with 6 mol of O₂.
when 1 mol of C₂H₅OH reacts with 6/2 mol of O₂,
then 0.3020 mol of C₂H₅OH reacts with - 6/2 x 0.3020
therefore number of O₂ moles reacted = 0.91 mol
        
                    
             
        
        
        
<u>Answer:</u> The molality of the solution is 0.1 m.
<u>Explanation:</u>
To calculate the molality of solution, we use the equation:

Where,
 = Given mass of solute = 27.1 g
 = Given mass of solute = 27.1 g
 = Molar mass of solute = 27.1 g/mol
 = Molar mass of solute = 27.1 g/mol
 = Mass of solvent = 100 g
 = Mass of solvent = 100 g
Putting values in above equation, we get:

Hence, the molality of the solution is 0.1 m.
 
        
                    
             
        
        
        
Explanation:
Steaming up or fogging happens when steam condenses on the mirror. Steam emerging from hot water can condense on a colder surface. That’s the reason you can see the result on a mirror instantaneously. Obviously, for a bathroom mirror to steam up, the steam that originates at the shower spray (or the bathtub) has to travel through the cooler air to reach the mirror. Since air tends to heat up easily, the mirror can steam up fast.
 
        
             
        
        
        
Answer:
I say for her to test her suspicion by going to see an allergist to diagnose the allergy.
 
        
             
        
        
        
Answer:
 1.7 × 10 ^42
Explanation:
Using Nernst equation
E°cell = RT/nF Inq 
at equilibrium
Q=K 
E°cell  = 0.0257 /n Ink= 0.0592/n log K 
Fe2+(aq)+2e−→Fe(s)     E∘= −0.45 V 
Ag+aq)+e−→Ag(s)         E∘= 0.80 V 
Fe(s)+2Ag+(aq)→Fe2+(aq)+2Ag(s)
balance the reaction
Fe → Fe²⁺ + 2e⁻  reversing for oxidation E° = 0.45 v
2 Ag⁺ +2e⁻ → 2Ag 
n = 2 moles  and K = equilibrium constant
E° cell = 0.80 + 0.45 = 1.25 V
E° cell = (0.0592 / n) log K  
substitute the value into the equations and solve for K
(1.25 × 2) / 0.0592  = log K
42.23 = log K 
k = 10^ 42.23
K = 1.7 × 10 ^42