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Marina86 [1]
3 years ago
7

If the crucible is contaminated with the volatile impurities. While heating, the impurity is then burned off and removed. Descri

be the error that has occurred; that is, is the reported mass percent of water in the hydrated salt too high or too low? Is the mass of the anhydrous salt remaining in the crucible reported as being too high or too low?
Chemistry
1 answer:
Art [367]3 years ago
6 0

Answer:

The presence of the contaminant increases the total mass.

And on continuous heating to remove the volatile impurities, the hydrated salt gets overheated and the anhydrous salt gets thermally decomposed thereby producing a gas.

The heating leads to the formation or release of a gas which leads to loss of a higher percentage of mass from the compound making the mass percent of water in the hydrated salt too high and the mass of the anhydrous salt remaining in the crucible too low.

Hydrated Salt            ⇒    Anhydrous salt         +       Water hydration

(C_{u}SO_{4} . 5H_{2}O)_{(s)}                (C_{u}SO_{4})_{(s)}                                 (5H_{2}O)_{(g)}

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The complete combustion of propane proceeds through the following reaction:
C_{3} H_{8} + 5O_{2} --> 3CO_{2} + 4H_{2}O

Combustion is an exothermic reaction, which means that it gives off heat as the reaction proceeds. For the complete combustion of propane, the heat of combustion is (-)2220 kJ/mole, where the minus sign indicates that the reaction is exothermic. 

The molar mass of propane is 44.1 grams/mole. Using this value, the number of moles propane to be burned can be determined from the mass of propane given. Afterwards, this number of moles is multiplied by the heat of combustion to give the total heat produced from the reaction of the given mass of propane.

 14.50 kg propane  x <u> 1000 g </u> x <u>  1 mole propane   </u>  x <u>  2220 kJ  </u>   
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2 years ago
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Answer:

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Step 1: Convert 826.1 mmHg to atm

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826.1 mmHg × 1 atm/760 mmHg = 1.087 atm

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We will use the conversion factor 101.3 J = 1 L.atm.

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w = P × ΔV

ΔV = w/P

ΔV = 4.223 L.atm/1.087 atm = 3.885 L

Step 4: Calculate the final volume

V₂ = V₁ + ΔV

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