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adoni [48]
3 years ago
8

To determine the types of equipment your boat must carry, you need to make a measurement of the boat. What is this measurement?

Physics
1 answer:
jenyasd209 [6]3 years ago
6 0

Explanation:

In total, the length is measured from the tip of the bow in a linear fashion to the stern of the formation of delight including any back-deck extensions. The measurement involves bow sprits; rudders; detachable engines and engine sections; handles; and various fittings and connections.

Importance in calculating a boat's length:

it affects the transportation costs (the longer the length, the higher the cost).   The pontoon's length counts as you find out how much rope you need to wrestle.  

The cost of vessel settlement on marinas depends in part on the pontoon length. As more area is consumed by a more drawn pontoon, the docking charges are higher.  

Transportation guidelines will probably not allow pontoons past a specific length on specific occasions of the day.

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in the same direction as the displacement vector and the motion

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4 years ago
Please need help on this
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#6 - Lower frequencies correspond to <em>longer</em> wavelengths.

#7 - To change the pitch of a sound, you have to change its <em>frequency</em>.

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4 years ago
Two cats are sitting on a 30 m hill. One cat
V125BC [204]

Answer:

Cat with 6 kg sitting on a 30 meter hill has greater potential energy.

Explanation:

gravitational potential energy (J) = mass (kg) × gravitational field × height (m)

<h3 /><h3><u>Note</u>:</h3>

gravitational field in Earth is 10 N/kg = <u>fixed unit</u>

<h3 /><h3><u>Given</u>:</h3>

1st Cat: 4 kg

2nd Cat: 6 kg

Both of their height is 30 meters.

<h3><u>Solve for g.p.e</u>:</h3>

1st cat = mgh = 4 × 10 × 30 = 1200 Joules

2nd cat = mgh = 6 × 10 × 30 = 1800 Joules

3 0
2 years ago
What is the density of a liquid that measures as 2 liters, and has a mass of 0.7 kilograms?
Vsevolod [243]
D=M/V = 0.7/2 = 0.35
4 0
3 years ago
Suppose the collision between the packages is perfectly elastic. To what height does the package of mass m rebound?
Hitman42 [59]

The height, h to which the package of mass m bounces to depends on its initial velocity, v and the acceleration due to gravity, g and is given below:

h = \frac{v^{2}}{2g}

<h3>What are perfectly elastic collision?</h3>

Perfectly elastic collisions are collisions in which the momentum as well as the energy of the colliding bodies is conserved.

In perfectly elastic collisions, the sum of momentum before collision is equal to the momentum after collision.

Also, the sum of kinetic energy before collision is equal to the sum of kinetic energy after collision.

Since some of the Kinetic energy is converted to potential energy of the body;

\frac{mv^{2}}{2} = mgh

h = \frac{v^{2}}{2g}

Therefore, the height to which the package m bounces to depends on its initial velocity and the acceleration due to gravity.

Learn more about elastic collisions at: brainly.com/question/7694106

7 0
2 years ago
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