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3 years ago

How many organ systems are found in the human body? a. 4. c. 11. b. 5. d. 15.

Physics

2 answers:

Kryger [21]3 years ago

6 0

Answer:The correct answer is option c.

Explanation;

Human body is made up total 11 organ system as follows:

Respiratory System : Encompasses with breathing organs : nose. lungs etc

Endocrine System : It comprised of organs which produced different hormones in human body.

Digestive System : System associated with digestion of food in human body.

Circulatory System : It consist of heart , blood vessels, blood which distributes nutrients and oxygen in whole human body.

Muscular System: this system provides locomotion and support to human body .

Skeleton System: System which provides structural support to the human body.

Lymphatic System : System responsible for formation of immune cell in human body.

Reproductive System : System responsible for the reproduction process.

Nervous System : This system controls and coordinates the movement of human body and its response to external and internal stimuli.

Excretory System : This system is responsible for removal of waste from human body.

Integumentary System : This system provide protection from the environment that is skin ,hair , nails etc.

ohaa [14]3 years ago

4 0

11 major systems are in the human body

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3 years ago

The angle between the two force of magnitude 20N and 15N is 60 degrees (20N force being horizontal) determine the resultant in m

BARSIC [14]

A) The resultant force is 30.4 N at $25.3^{\circ}$

B) The resultant force is 18.7 N at $43.9^{\circ}$

Explanation:

In order to find the resultant of the two forces, we must resolve each force along the x- and y- direction, and then add the components along each direction to find the components of the resultant.

The two forces are:

$F_1 = 20 N$ at $0^{\circ}$ above x-axis

$F_2 = 15 N$ at $60^{\circ}$ above y-axis

Resolving each force:

$F_{1x}=F_1 cos \theta = (20)(cos 0)=20 N\\F_{1y}=F_1 sin \theta =(20)(sin 0)=0 N$

$F_{2x}=F_2 cos \theta = (15)(cos 60)=7.5 N\\F_{2y}=F_2 sin \theta =(15)(sin 60)=13.0 N$

So, the components of the resultant are:

$F_x = F_{1x}+F_{2x}=20+7.5 = 27.5 N\\F_y = F_{1y}+F_{2y}=0+13.0=13.0 N$

And the magnitude of the resultant is:

$F=\sqrt{F_x^2+F_y^2}=\sqrt{27.5^2+13.0^2}=30.4 N$

And the direction is:

$\theta=tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{13.0}{27.5})=25.3^{\circ}$

In this case, the 15 N is applied in the opposite direction to the 20 N force. Therefore we need to re-calculate its components, keeping in mind that the angle of the 15 N force this time is

$\theta=180^{\circ}-60^{\circ}=120^{\circ}$