1. The mass of 1.33×10²² mole of Sb is 1.62×10²⁴ g
2. The mass of 4.75×10¹⁴ mole of Pt is 9.26×10¹⁶ g
3. The mass of 1.22×10²³ mole of Ag is 1.32×10²⁵ g
4. The mass of 9.85×10²⁴ mole of Cr is 5.12×10²⁶ g
<h3>1. Determination of the mass of 1.33×10²² mole of Sb</h3>
- Mole of Sb = 1.33×10²² mole
- Molar mass of Sb = 122 g/mol
Mass = mole × molar mass
Mass of Sb = 1.33×10²² × 122
Mass of Sb = 1.62×10²⁴ g
<h3>2. Determination of the mass of 4.75×10¹⁴ mole of Pt</h3>
- Mole of Pt = 4.75×10¹⁴ mole
- Molar mass of Pt = 122 g/mol
Mass = mole × molar mass
Mass of Pt = 4.75×10¹⁴ × 195
Mass of Pt = 9.26×10¹⁶ g
<h3>3. Determination of the mass of 1.22×10²³ mole of Ag</h3>
- Mole of Ag = 1.22×10²³ mole
- Molar mass of Ag = 108 g/mol
Mass = mole × molar mass
Mass of Ag = 1.22×10²³ × 108
Mass of Ag = 1.32×10²⁵ g
<h3>4. Determination of the mass of 9.85×10²⁴ mole of Cr</h3>
- Mole of Cr = 9.85×10²⁴ mole
- Molar mass of Cr = 52 g/mol
Mass = mole × molar mass
Mass of Cr = 9.85×10²⁴ × 52
Mass of Cr = 5.12×10²⁶ g
Learn more about mole:
brainly.com/question/13314627
Answer: The correct answer is: " endothermic . "
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<u>Note</u>: Heat flows <u> into </u> [heat <u> may be </u> absorbed within] an "<u>endothermic</u>" reaction or system
To the contrary, heat flows <u> </u><u>out </u> [heat <u> may </u><em> </em>exit from or <u> may be </u> released from] an "<u>exothermic</u>" reaction or process.
<u>Hint</u>: Think of the "prefixes" of: "<u>endo</u>thermic" and "<u>exo</u>thermic" :
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1) endo- = "within" (as in "endothermic" —heat tends to be absorbed/"within"/"released within"/released within"/into" ;
2) exo- = " outwards"/"exit" (as in "exothermic") —heat tends to '"exit"/leave/escape from/"be released out of/form".
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Hope this is helpful to you!
Best wishes to you in your academic pursuits
—and within the "Brainly" community"!
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Answer:
-Cations: They are formed by an atom losing an electron or electrons.
-Anions: They are formed by an atom gaining an electron or electrons.
Answer: 0.225 atm
Explanation:
For this problem, we have to use Boyle's Law.
Boyle's Law: P₁V₁=P₂V₂
Since we are asked to find P₂, let's manipulate the equation.
P₂=(P₁V₁)/V₂
With this equation, the liters cancel out and we will be left with atm.
P₂=0.225 atm
