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Crazy boy [7]
3 years ago
15

A worker pushes horizontally on a large crate with a force of 170 N, and the crate is moved 3.6 m. How much work was done

Physics
1 answer:
Mariulka [41]3 years ago
8 0

W = F * D

W = 170 N * 3.6 M

W = 612 J

You can use this format to answer questions where you're given the force and distance.

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Three dogs are fighting over a bone. One is pulling to the left with a force of 20N, another
Len [333]

Answer:

<em>Net force = 21.12 N</em>

<em>angle for the force α = 45°</em>

Explanation:

<em>In this problem, we will take the left as the negative x-axis, the right as the positive x-axis, and the upward direction as the positive y-axis.</em>

The 20 N force to the left has an x component of -20 N, and y component of 0 N

The 35 N force to the right has a x component of 35 N, and a y component of 0 N

The 15 N upwards has an x component of 0 N, and a y component of 15 N

We resolve the forces into the x and y components.

for the x component Fx

Fx = -20 + 35 + 0 = 15 N

For the y component Fy

Fy = 0 + 0 + 15 = 15 N

Net force Fn = \sqrt{Fx^{2} + Fy^{2}  }

Fn = \sqrt{(15)^{2} + (15^{2} ) }

<em>Net force Fn = 21.21 N</em>

for the angle,

tan\alpha = \frac{Fy}{Fx} = \frac{15}{15}

tan\alpha = 1

α = tan^{-1} 1

<em>angle for force α = 45°</em>

8 0
3 years ago
We are on an asteroid with thrusters pointed in 4 directions; Go Left, GO Right, Go Up, and Go Down. We start at coordinate (3,3
GalinKa [24]
we would be at (4,0)
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3 years ago
A resistor rated at 250 k Ω is connected across two D cell batteries (each 1.50 V) in series, with a total voltage of 3.00 V. Th
Andrej [43]

Given Information:  

Resistance = R = 250 Ω

Voltage = V = 3 V

Tolerance =   ±5%

Required Information:  

Maximum current = Imax = ?

Minimum current = Imin = ?

Answer:  

Imax = 12.6 uA

Imin = 11.4 uA

Explanation:  

As we know from Ohm's law

I = V/R

The current will be maximum when R is minimum and the current will be minimum when R is maximum

Rmax = 250,000 + 0.05*250,000

Rmax = 250,000 + 12500

Rmax = 262500 Ω

Rmin = 250,000 - 0.05*250,000

Rmin = 250,000 - 12500

Rmin = 237500 Ω

Imax = V/Rmin

Imax = 3/237500

Imax = 12.6 uA

Imin = V/Rmax

Imin = 3/262500

Imin = 11.4 uA

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UHHHHHH yes...... well depends on what the question is asking but more times then not  yes they matter. 
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It is true 

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