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3 years ago

Please help ASAP I will mark brainliest

Physics

2 answers:

likoan [24]3 years ago

5 0

Answer:

arrow c tell me if im incorect

Explanation:

chubhunter [2.5K]3 years ago

3 0

The answer is arrow c

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What do all the items that light up a bulb have in common? (help)

kipiarov [429]

Answer:

Light bulbs started off with elements made of carbon, but over the years inventors added new elements such as tungsten, mercury, chlorine and europium to their toolkits

Explanation:

8 0

3 years ago

The wet density of a gravel was found to be 2.32 Mg/m^3 and the field water content was 16%. In the laboratory, the density of t

Sholpan [36]

Answer:

the relative density of the gravel in the field is 0.7365 or 73.65%

Explanation:

Given that;

wet density of gravel $r_{b}$ = 2.3 Mg/m³

field water content w = 16%

density of solids in lab $r_{s}$ = 2.70 Mg/m³

Maximum void ratio $e_{max}$ = 0.59

Minimum void ratio $e_{mini}$ = 0.28

first we determine the dry density of gravel $r_{d}$ = $r_{b}$ / 1+ w

$r_{d}$ = 2.3 Mg/m³ / 1 + 0.16 = 2.3/1.16 = 1.9827 Mg/m³

we know that; $r_{w}$ = 1000 kg/m³ = 1 g/cm³

Specific Gravity of soil G = $r_{s}$ / $r_{w}$ = 2.70 Mg/m³ / 1 = 2.70 Mg/m³

eo = ((G× $r_{w}$ )/ $r_{d}$ ) - 1

eo = (( 2.70 × 1) / 1.9827 ) - 1

eo = 1.3617 - 1

Co = 0.3617

so Relative density $I_{D}$ will be;

$I_{D}$ = $e_{max}$ - eo / $e_{max}$ - $e_{mini}$

we substitute

$I_{D}$ = 0.59 - 0.3617 / 0.59 - 0.28

$I_{D}$ = 0.2283 / 0.31

$I_{D}$ = 0.7365 or 73.65%

Therefore; the relative density of the gravel in the field is 0.7365 or 73.65%

3 0

3 years ago

Water at 20oC flows through a long elliptical duct 30 cm wide and 22 cm high. What average velocity, in m/s, would cause the wei

mars1129 [50]

Explanation:

The given data is as follows.

Fluid is water so, density $\rho = 1000 kg/m^{3}$

Weight flow rate = 500 lbf/s = 2224.11 N/sec

Cross-sectional area (A) = $\pi \times \frac{30}{2} \times \frac{22}{2}$

= 0.05184 $m^{2}$

Hence, weight flow rate will be given as follows.

w = $\rho \times g \times A \times V$

2224.11 N/sec = $\rho \times g \times A \times V$

V = $\frac{2224.11}{1000 \times 9.81 \times 0.05184}$ m/s

= 4.373 m/s

Thus, we can conclude that average velocity in the given case is 4.373 m/s.

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3 years ago

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Which idea did Ptolemy's model use to explain why the planets appeared to move backward as they moved in their orbits? The plane

ruslelena [56]

Answer:

The planets spun in epicycles.

Explanation:

The planets were not simply attached to a mystical sphere (“deferent”) but they were actually attached to a mini-sphere (“epicycle”) which rotated on the larger one.

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3 years ago

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Dos cargas iguales de 10^-7C estan separadas por una distancia de 2m. calcule la fuerza con que se repelen

m_a_m_a [10]

Answer:

$F=2.25\times 10^{-5}\ N$