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Mamont248 [21]
3 years ago
6

a projectile is shot horizontally from the edge of a cliff, 230m above the ground. the projectile lands 300m from base of the cl

iff​
Physics
1 answer:
bekas [8.4K]3 years ago
7 0

Answer:

The time taken by the projectile to hit the ground is 6.85 sec.

Explanation:

Given that,

Vertical height of cliff = 230 m

Distance = 300 m

Suppose, determine the time taken by the projectile to hit the ground.

We need to calculate the time

Using second equation of motion

s=ut+\dfrac{1}{2}gt^2

Where, s = vertical height of cliff

u = initial vertical velocity

g = acceleration due to gravity

Put the value in the equation

230=0+\dfrac{1}{2}\times9.8\times t^2

t=\sqrt{\dfrac{230\times2}{9.8}}

t=6.85 sec

Hence, The time taken by the projectile to hit the ground is 6.85 sec.

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Answer:

it is separated by 80 cm distance

Explanation:

As per Coulombs law we know that force between two point charges is given by

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force between two charges is given as

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Answer:

The energy of the capacitors connected in parallel is 0.27 J

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Answer:

A tornado can, surprisingly, cause a supercell, so the answer would be C.) tornado

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Afterthought:

<em>Please give BRAINLEST!</em>

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