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3 years ago

According to Reference Table J, which of these

Chemistry

1 answer:

Alborosie3 years ago

8 0

Answer:

Cr^3

Explanation:

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Fill in the blank for these q’s

kolezko [41]

Plant cells are rectangular or squarish in shape.

Plant cells have a large vacuole.

7 0

3 years ago

Read 2 more answers

N2H4+H2O2 ——> N2+H2O coefficient

const2013 [10]

Answer:

N2H4 + 2H2O2 ---->N2 + 4H2O

Explanation:

N=2 N=2

H=6 ->8 H=2 ->8

O=2 -> 4 O=1 -> 4

Add coefficients to hydrogen peroxide on the left and water on the right, so that there is an equal number of hydrogens and oxygens.

3 0

3 years ago

The electron affinity of Bi is -94.6 kJ and the value for At is -280 kJ. What is the approximate electron affinity for Po?

lys-0071 [83]

Answer:

48 KJ mol-1

Explanation:

3 0

3 years ago

Is there a mathematical pattern in the number of

aleksandrvk [35]

Answer:

The orbital shapes are actually representation of (Ψ)2 all over the orbit simplified ... ψnlml(r,θ,ϕ)=Rnl(r)Ymll(θ,ϕ) , ... and thus it is directly linked to the angular and radial nodes. ... for different quantum values(which can be assigned to different orbitals are ) .... The two types of nodes are angular and radial.

Explanation:

hope it helps

4 0

3 years ago

Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4

inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

$M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol$

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

$M=\frac{n_{solute}}{V_{solution}}$

So you can solve for the moles of the solute:

$n_{solute}=M*V_{solution}$

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

$n_{solute}=1mol/L*1.5L=1.5mol$

But this is just a supposition.

Regards.

4 0

3 years ago