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Naily [24]
3 years ago
6

The charges on two metallic balls are 5.0 and 7.0 coulombs respectively. They are kept 1.2 meters apart. What is the force of in

teraction between the two? (k = 9.0 * 10© newton·metersÆ/coulombÆ)
Physics
1 answer:
Marysya12 [62]3 years ago
5 0
We know, F = k * q₁ * q₂ / r²

Substitute the known values, 
F = 9 * 10⁹ * 5 * 7 / (1.2)²

F = 315 * 10⁹ / 1.44

F = 218.75 * 10⁹ N

F = 2.1875 * 10¹¹ N   [ Final Answer ]

Hope this helps!
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3 years ago
A mass M is suspended from a spring and oscillates with a period of 0.840 s. Each complete oscillation results in an amplitude r
iren [92.7K]

The energy becomes 0.50 times in 6.72 s.

Let E represent the oscillator's initial energy, Et be the energy's final value at time t, where A is its beginning amplitude, At amplitude at time t, be. as the oscillator's energy increases to 0.50 times its initial value. We can replace the oscillator's total energy for the energy at time t to obtain the amplitude as shown below.

Et=0.50E

1

k(4₂)² = (0.5) - kA²

(4₂)² = (0.5) A²

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So, the amplitude of the oscillator becomes 0.71 times its initial ar

0.71A = = A(0.96)¹2

log(0.71)

log(0.96)

8.4

n=

So, the time taken for n oscillation is obtained as,

t = n (0.800 s)

= (8.4) (0.800)

= 6.72 s

learn more about oscillators brainly.com/question/15169199

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