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3 years ago

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The charges on two metallic balls are 5.0 and 7.0 coulombs respectively. They are kept 1.2 meters apart. What is the force of in

teraction between the two? (k = 9.0 * 10© newton·metersÆ/coulombÆ)

1 answer:

Marysya12 [62]3 years ago

5 0

We know, F = k * q₁ * q₂ / r²

Substitute the known values,
F = 9 * 10⁹ * 5 * 7 / (1.2)²

F = 315 * 10⁹ / 1.44

F = 218.75 * 10⁹ N

F = 2.1875 * 10¹¹ N [ Final Answer ]

Hope this helps!

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Emerging adults are typically financially independent from their parents.<br> True or false?

zmey [24]

Answer:

False

Explanation:

According to USA today "Though nearly 60% of the 18 to 21 year olds surveyed said they have a job, and 70% of the 22 to 26 year olds said the same, many seem to rely on mom and dad to fund non-essential expenses. Nearly 75% of the 18 to 21 year olds and more than 40% of 22 to 26 year olds said their parents pay their monthly cell phone bill. Just 54% of 22 to 26 year olds own or lease their own car; and 43% of 22 to 26 year olds are living at home with their parents."

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2 years ago

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Gretchen runs the first 4.0 km of a race at 5.0 m/s. Then a stiff wind comes up, so she runs the last 1.0 km at only 4.0 m/s.

KIM [24]

Answer:

The velocity is $v = 4.76 \ m/s$

Explanation:

From the question we are told that

The first distance is $d_1 = 4.0 \ km = 4000 \ m$

The first speed is $v_1 = 5.0 \ m/s$

The second distance is $d_2 = 1.0 \ km = 1000 \ m$

The second speed is $v_2 = 4.0 \ m/s$

Generally the time taken for first distance is

$t_1 = \frac{d_1 }{v_1 }$

$t_1 = \frac{4000}{5}$

$t_1 = 800 \ s$

The time taken for second distance is

$t_1 = \frac{d_2 }{v_2 }$

$t_1 = \frac{1000}{4}$

$t_1 = 250 \ s$

The total time is mathematically represented as

$t = t_1 + t_2$

=> $t = 800 + 250$

=> $t = 1050 \ s$

Generally the constant velocity that would let her finish at the same time is mathematically represented as

$v = \frac{d_1 + d_2}{t }$

=> $v = \frac{4000 + 1000}{1050 }$

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3 years ago

An object has 16N of force being applied to the right, 16N of force being applied to the left, and 4N of force being applied dow

goldenfox [79]

Answer:

4N downward

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2 years ago

At what speed do a bicycle and its rider, with a combined mass of 100 kg, have the same momentum as a 1400 kg car traveling at 6

Ilia_Sergeevich [38]

Momentum of car

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Formula: P = mv

P = (1,400 Kg)(6.0 m/s)

P = 8,400 Kg.m/s

Velocity of the rider to have the same momentum as a car.

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2 years ago

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Answer:

The frequency of the oscillations in terms of fo will be f2=fo/3

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⇒f2=fo\3

Here frequency f is inversely poportional to square root of mass m.

so the value of remainder of frequency f2 and fo is equal to 1:3.

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⇒ $\frac{f2}{fo}$ = 1:3

⇒f2= $\frac{fo} {3}$

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2 years ago